Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

An experiment is being planned to compare the effects of several diets on the weight gain of beef cattle, measured over a 140 -day test period. 20 In order to have enough precision to compare the diets, it is desired that the standard error of the mean for each diet should not exceed 5 kg. (a) If the population standard deviation of weight gain is guessed to be about 20 kg on any of the diets, how many cattle should be put on each diet in order to achieve a sufficiently small standard error? (b) If the guess of the standard deviation is doubled, to 40 kg, does the required number of cattle double? Explain.

Short Answer

Expert verified
For part (a), 16 cattle are needed for each diet to not exceed the desired SE of 5 kg. For part (b), the required number of cattle quadruples to 64, not doubles, when the guessed standard deviation is doubled to 40 kg.

Step by step solution

01

Understanding the Requirement for Standard Error

The standard error (SE) of the mean is given by the formula SE=σn, where σ is the population standard deviation and n is the sample size. The problem states that the SE should not exceed 5 kg.
02

Solving for the Sample Size (n)

To find the sample size needed to achieve the desired SE, rearrange the formula to solve for n and plug in the values of σ=20 kg and SE=5 kg: n=(σSE)2=(205)2=16.
03

Considering the Effect of Doubling the Standard Deviation

Doubling the standard deviation to 40 kg would affect the sample size required to achieve the same SE. The new sample size is calculated using the modified standard deviation: n=(σSE)2=(405)2=64.
04

Comparing the Two Sample Sizes

Comparing the two sample sizes calculated for the two standard deviation guesses: With σ=20 kg, we calculated n=16, and with σ=40 kg, we calculated n=64. Even though the standard deviation was doubled, the required number of cattle did not double; it actually quadrupled.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size Calculation
Determining the right sample size is a cornerstone in quantitative research, particularly in experimental studies like the one described in our exercise. Calculating the sample size involves understanding the desired precision of the results. In this case, the desired accuracy is influenced by the standard error (SE), which should not exceed 5 kg for weight gain. To keep SE low, a larger sample size is typically required.

The sample size (n) is calculated using the formula: n=(σSE)2. As we've seen in the solution, with an estimated population standard of 20 kg, we need 16 cattle. Doubling the standard deviation requires adjusting the sample size to maintain the same standard error; thus, we quadruple the number of cattle to 64, not double, due to the squared relationship in the formula.
Population Standard Deviation
The population standard deviation (σ) is a measure of how much individual measurements in a population deviate from the population mean. It's vital for determining the variability of the data, which directly affects the required sample size for an experiment. A higher standard deviation indicates more variability, leading to a larger sample needed to achieve a certain level of precision in estimating the mean.
In our scenario, with σ=20 kg, less data is needed to reach the desired standard error compared to when σ=40 kg. It's also important to understand that the population standard deviation is an estimate, and a change in this estimate can have significant implications for the design of a study, as it dramatically alters the required sample size.
Quantitative Research Methodology
Quantitative research methodology is a structured way of collecting and analyzing data to quantify the problem and create statistical models to test hypotheses. It typically involves objective measurements and the statistical, mathematical, or computational analysis of data collected through polls, surveys, and questionnaires, or by manipulating pre-existing statistical data.

In our exercise, the quantitative research method would comprise several critical steps: forming a clear hypothesis about diets' effects on weight gain, planning the data collection procedure, such as deciding on the sample size and ensuring measurement precision, and finally, statistically analyzing the data to draw conclusions about the dietary effects. The standard error and population standard deviation play crucial roles in quantitative research in determining the reliability and generalizability of the experiment's outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Researchers were interested in the short-term effect that caffeine has on heart rate. They enlisted a group of volunteers and measured each person's resting heart rate. Then they had each subject drink 6 ounces of coffee. Nine of the subjects were given coffee containing caffeine, and 11 were given decaffeinated coffee. After 10 minutes each person's heart rate was measured again. The data in the table show the change in heart rate; a positive number means that heart rate went up, and a negative number means that heart rate went down. 47 (a) Use these data to construct a 90% confidence interval for the difference in mean effect that caffeinated coffee has on heart rate, in comparison to decaffeinated coffee. [Note: Formula (6.7.1) yields 17.3 degrees of freedom for these data. (b) Using the interval computed in part (a) to justify your answer, is it reasonable to believe that caffeine may not affect heart rates? (c) Using the interval computed in part (a) to justify your answer, is it reasonable to believe that caffeine may affect heart rates? If so, by how much? (d) Are your answers to (b) and (c) contradictory? Explain.  Caffeine  Decaf 28261113014424414181628201810n911y¯7.35.9s11.111.2 SE 3.73.4

A zoologist measured tail length in 86 individuals, all in the 1-year age group, of the deermouse Peromyscus. The mean length was 60.43 mm and the standard deviation was 3.06 mm. A 95% confidence interval for the mean is (59.77,61.09) (a) True or false (and say why): We are 95% confident that the average tail length of the 86 individuals in the sample is between 59.77 mm and 61.09 mm. (b) True or false (and say why): We are 95% confident that the average tail length of all the individuals in the population is between 59.77 mm and 61.09 mm.

Red blood cell counts (103X cells per mm3 ) of 15 lizards had an average of 843.4. The SD and the SE were, in random order, 64.9 and 251.2. Which is the SD, and which is the SE? How do you know?

A study was conducted to determine whether relaxation training, aided by biofeedback and meditation, could help in reducing high blood pressure. Subjects were randomly allocated to a biofeedback group or a control group. The biofeedback group received training for 8 weeks. The table reports the reduction in systolic blood pressure (mmHg) after eight weeks. 42[ Note: Formula (6.7.1) yields 190 degrees of freedom for these data. (a) Construct a 95% confidence interval for the difference in mean response. (b) Interpret the confidence interval from part (a) in the context of this setting.  Biofeedback  Control n9993y¯13.84.0 SE 1.341.30

Is the nutrition information on commercially produced food accurate? In one study, researchers sampled 13 packages of a certain frozen reduced-calorie chicken entrée with a reported calorie content of 252 calories per package. The mean calorie count of the sampled entrées was 306 with a sample standard deviation of 51 calories. 59 (a) Compute a 90% confidence interval for the population mean calorie content of the frozen entrée. (b) Compute a 99% confidence interval for the population mean calorie content of the frozen entrée. (c) Based on the two intervals computed in parts (a) and (b), what do you think about the reported calorie content for this entrée?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free