Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In a certain college, \(55 \%\) of the students are women. Suppose we take a sample of two students. Use a probability tree to find the probability (a) that both chosen students are women. (b) that at least one of the two students is a woman.

Short Answer

Expert verified
The probability that (a) both chosen students are women is 0.3025, and (b) that at least one of the two students is a woman is 0.775.

Step by step solution

01

Determining the Probabilities for Each Branch

First, set up a probability tree with two levels, each with two branches. The first branch represents choosing a woman or a man for the first student, and the second level of branches represents choosing a woman or a man for the second student. The probability of choosing a woman is 0.55 and thus the probability of choosing a man is 1 - 0.55 = 0.45.
02

Calculating the Probability of Both Students Being Women

To find the probability of both students being women, follow the branches that represent choosing a woman first and a woman second. Multiply the probabilities along the branches: 0.55 (first woman) * 0.55 (second woman).
03

Calculating the Probability of At Least One Woman

To find this probability, calculate the probability of all scenarios with at least one woman and add them together. There are three possibilities: Woman-Woman, Woman-Man, and Man-Woman. Add the probabilities of these branches together.
04

Finding the Probability of Woman-Man and Man-Woman

Calculate the probability of the Woman-Man branch: 0.55 (first woman) * 0.45 (second man). Calculate the probability of the Man-Woman branch: 0.45 (first man) * 0.55 (second woman).
05

Summing All Probabilities for At Least One Woman

Add up the probabilities for the following branches: Woman-Woman, Woman-Man, and Man-Woman. Be careful to not include the Man-Man branch as it does not satisfy the condition of having at least one woman.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Tree
When breaking down complicated probability problems, a probability tree is an excellent visual tool that helps elucidate possible outcomes and their associated probabilities. It's like a map that guides you through all the potential scenarios. Let's take the given exercise of selecting students as an example. Imagine two branches stemming from a starting point: one representing the selection of a woman (with a probability of 0.55) and the other a man (with a probability of 0.45). This forms the first level of the tree.

As we add a second level for the second student selection, the tree expands, showing all possible combinations of the first and second choices. By multiplying the probabilities along the branches, we can determine the likelihood of specific outcomes, such as both students being women. This is not only a practical approach to visualize the problem but also an effective way to calculate combined probabilities.
Sample Probability
The concept of sample probability is about determining the likelihood of a particular outcome within a smaller, representative group from a larger population. It's like taking a snapshot of the broader group to predict what could happen. In the college student example, we focus on the probability of a random sample of two students.

By considering the sampling of two students independently, we apply sample probability to gauge the chances of each possible pair - whether it's Woman-Woman, Woman-Man, or Man-Woman. Understanding sample probabilities allows for the prediction of outcomes even when dealing with more complex populations and larger sample sizes.
Combining Probabilities
In the world of probability, combining probabilities is a foundational skill. It involves calculating the likelihood of two or more events happening together. For instance, when we're looking at both students being women or at least one being a woman, we're essentially combining the individual probabilities of picking a woman or a man each time.

It involves simple multiplication for independent events—as seen in the Woman-Woman case (0.55 for the first and 0.55 for the second) — and addition for events that are not mutually exclusive, such as calculating the likelihood of having at least one woman in the sample. Intuitively, it's like piecing together a puzzle where each piece is a different scenario and the complete picture is the total probability for the event.
Probability Theory
At its core, probability theory is a branch of mathematics dealing with the study of random events and quantifying the likelihood of these events occurring. It's the toolbox that has everything statisticians need to analyze random phenomena. From basic operations like calculating the probability of an event to more complex concepts such as random variables and distributions, probability theory is the foundation of statistical analysis.

It equips us with principles and formulas to make sense of uncertainty. Whether we're dealing with a simple coin flip or the prediction of market trends, probability theory is the framework that helps us navigate through the inherently unpredictable nature of the world.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Australia, \(16 \%\) of the adult population is near- sighted. 17 If three Australians are chosen at random, what is the probability that (a) two are nearsighted and one is not? (b) exactly one is nearsighted? (c) at most one is nearsighted? (d) none of them are nearsighted?

The following table shows the distribution of ages of Americans. \({ }^{3}\) Age distribution in reference population $$ \begin{array}{|cc|} \hline \text { Age } & \text { Proportion } \\ \hline 0-19 & 0.27 \\ 20-29 & 0.14 \\ 30-39 & 0.13 \\ 40-49 & 0.14 \\ 50-64 & 0.19 \\ 65+ & 0.13 \\ \hline \end{array} $$ Find the probability that the age of a randomly chosen American (a) is less than 20 . (b) is between 20 and \(49 .\) (c) is greater than \(49 .\) (d) is greater than \(29 .\)

A certain drug treatment cures \(90 \%\) of cases of hookworm in children. \({ }^{18}\) Suppose that 20 children suffering from hookworm are to be treated, and that the children can be regarded as a random sample from the population. Find the probability that (a) all 20 will be cured. (b) all but 1 will be cured. (c) exactly 18 will be cured. (d) exactly \(90 \%\) will be cured.

If a woman takes an early pregnancy test, she will either test positive, meaning that the test says she is pregnant, or test negative, meaning that the test says she is not pregnant. Suppose that if a woman really is pregnant, there is a \(98 \%\) chance that she will test positive. Also, suppose that if a woman really is not pregnant, there is a \(99 \%\) chance that she will test negative. (a) Suppose that 1,000 women take early pregnancy tests and that 100 of them really are pregnant. What is the probability that a randomly chosen woman from this group will test positive? (b) Suppose that 1,000 women take early pregnancy tests and that 50 of them really are pregnant. What is the probability that a randomly chosen woman from this group will test positive?

Suppose that a student who is about to take a multiple choice test has only learned \(40 \%\) of the material covered by the exam. Thus, there is a \(40 \%\) chance that she will know the answer to a question. However, even if she does not know the answer to a question, she still has a \(20 \%\) chance of getting the right answer by guessing. If we choose a question at random from the exam, what is the probability that she will get it right?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free