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Fidelity of protein synthesis The average mass of proteins in the cell is 30,000 Da, and the average mass of an amino acid is 120 Da. In eukaryotic cells, the translation rate for a single ribosome is roughly 40 amino acids per second. (a) The largest known polypeptide chain made by any cell is titin. It is made by muscle cells and has an average weight of \(3 \times 10^{6}\) Da. Estimate the translation time for titin and compare it with that of a typical protein. (b) Protein synthesis is very accurate: for every 10,000 amino acids joined together, only one mistake is made. What is the probability of an error occurring for one amino acid addition? What fraction of average sized proteins are synthesized error-free?

Short Answer

Expert verified
The translation time for a typical protein is about 6.25 seconds, while for titin, it is about 625 seconds, which is 100 times longer. The error rate per amino acid addition is 0.01%, thus the fraction of average-sized proteins synthesized without any mistake is around 98%.

Step by step solution

01

Calculate the number of amino acids in a protein

To calculate the number of amino acids in a protein, divide the total mass of the protein by the mass of an individual amino acid. For a typical protein, this would be \(\frac{30000}{120}=250\) and for titin, \(\frac{3 \times 10^{6}}{120}=25,000\).
02

Calculate the translation time for proteins

To calculate how long it takes for a protein to be synthesized, divide the number of amino acids in the protein by the translation rate. For a typical protein, this is \(\frac{250}{40}\approx6.25\) seconds and for titin, \(\frac{25000}{40}=625\) seconds.
03

Compare the translation times

Comparing the translation time for a typical protein to that of titin, it can be observed that titin takes approximately 100 times longer to synthesize.
04

Calculate the error per amino acid

The error rate for a single amino acid addition is given as one error in every 10,000 amino acids. The probability can thus be calculated as \(\frac{1}{10000}=0.0001\) or 0.01%.
05

Calculate the fraction of error-free proteins

To calculate the fraction of average-sized proteins synthesized without any mistake, raise the probability of success (i.e., no error) of a single amino acid addition to the power equivalent to the number of amino acids in the protein. This results in \((1-0.0001)^{250}\approx0.98\), or 98%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Translation Rate
The translation rate is a measure of how quickly a ribosome can add amino acids to a growing polypeptide chain during protein synthesis. In eukaryotic cells, a single ribosome synthesizes about 40 amino acids per second. Understanding this rate is critical when estimating how long it will take for a protein to be fully synthesized.

For example, an average-sized protein with a mass of 30,000 Da composed of about 250 amino acids would take approximately 6.25 seconds to synthesize at this rate. This rapid assembly allows cells to respond quickly to changes in their environment by producing the proteins necessary for survival and function. Translation rate is a balance between speed and accuracy; although the ribosome works quickly, it must also ensure that each amino acid is correctly incorporated to maintain protein function.
Ribosome Function
Ribosomes play a critical role in the essential biological process of protein synthesis, acting as the site where genetic information is translated into proteins. They are complex molecular machines composed of ribosomal RNA (rRNA) and proteins, functioning to read messenger RNA (mRNA) sequences and translate them into polypeptide chains.

During translation, ribosomes move along an mRNA strand, match the mRNA codons with the correct transfer RNA (tRNA) molecules, and link the amino acids carried by tRNA into a polypeptide chain. This chain will fold into a functional protein after release from the ribosome. Ribosome's function is highly intricate, requiring not only the precise matching of codons to amino acids but also the correct binding, peptidyl transfer, and movement along the mRNA, all of which contribute to the fidelity of protein synthesis.
Polypeptide Chain
A polypeptide chain is a sequence of amino acids linked together by peptide bonds and is the primary structure of a protein. The specific sequence of amino acids determines the protein's unique structure and function.

The formation of a polypeptide chain is a critical step in protein synthesis, with ribosomes playing a central role in joining amino acids one at a time in the correct order. After synthesis, the polypeptide chain undergoes folding and sometimes chemically modifies before becoming a fully functioning protein. As exemplified by titin, the largest known polypeptide chain, which weighs approximately 3 million Da and contains around 25,000 amino acids, even large proteins are synthesized effectively by the cell's translation machinery.
Amino Acid
Amino acids are the building blocks of proteins. Every amino acid consists of a central carbon atom bonded to an amino group, a carboxyl group, a hydrogen atom, and a variable side chain (R group). There are 20 different standard amino acids, each with unique properties provided by its side chain.

The sequence and nature of the amino acids in a polypeptide chain determine the protein's structure and function. Amino acids are linked by peptide bonds during translation to form proteins, with a typical amino acid weighing approximately 120 Da. The precise addition of amino acids in the correct order is crucial for the synthesis of error-free proteins.
Error Rate in Protein Synthesis
Protein synthesis is a highly accurate process, but errors can occur. The average error rate is about one mistake for every 10,000 amino acids added, which translates to a 0.01% chance of an error in any single addition. Although this error rate may seem small, the accumulation of errors can have significant consequences for protein function.

For an average-sized protein consisting of 250 amino acids, approximately 98% are synthesized without any mistakes. However, the longer the polypeptide chain, the higher the chance that an error will occur during its synthesis. It is the cell's quality control mechanisms, such as proofreading functions by the ribosome and the protein repair systems, that help to maintain such high fidelity in protein synthesis.

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Most popular questions from this chapter

Restriction enzymes and sequences (a) Restriction enzymes are proteins that recognize specific sequences at which they cut the DNA. Two commonly used restriction enzymes are HindIII and EcoRI. Look up the recognition sequences that these enzymes each cut and make a sketch of the pattern of cutting they carry out. Consider the approximately 48,000 bp genome of lambda phage and make an estimate of the lengths of the fragments that you would get if the DNA is cut with both the HindIII and EcoRI restriction enzymes. There is a precise mathematical way to do this and it depends upon the length of the recognition sequence-a 5 cutter will have shorter fragments than an 8 cutter-explain that. (b) Find the actual fragment lengths obtained in the lambda genome using these restriction enzymes by going to the New England Biolabs website (www.neb.com) and looking up the tables identifying the sites on the lambda genome that are cut by these different enzymes. How do these cutting patterns compare with your results from (a)? (c) Plot the number of cuts in the lambda genome as a function of the length of the recognition sequence of several commercially available type II restriction enzymes. You can download the list of type II restriction enzymes from the book's website. Combine this plot with a curve showing your theoretical expectation.

Mutations of bacteria in our gut (a) The populations of the \(E\). coli in the guts of a collection of humans can be large enough that multiple mutations can occur simultaneously in one bacterium. Suppose that a very particular combination of \(k\) point mutations is required for a pathogenic strain to emerge and that these must all arise in one cell division (as could be the case if the subsets of these mutations are deleterious). With the point mutation rate per base pair per cell division of \(\mu,\) what is the probability \(m_{k}\) that this occurs in a single cell division? The simplest assumption is that the probabilities of the different mutations are independent. (b) In a human large intestine, the density of bacteria is estimated to be about \(10^{11.5}\) per milliliter, of which a fraction of about \(10^{-4}\) are \(E\) coll. Estimate how many \(E\) coli per person this implies. In a population of \(N\) humans, with \(n\) \(E\) coli in each of their guts, in \(T\) generations of the \(E\). coli estimate the total probability \(P_{k}\) that the particular combination of \(k\) mutations occurs at least once. (c) With the population of Silicon Valley over one year, what are the chances this occurs for \(k=2 ?\) For \(k=3 ?\) Some crucial factors in your estimate are \(\mu \approx 10^{-10}-10^{-9}\) mutations per base pair per cell division and the generation time of \(\bar{E}\). colt. the standard lab result is that \(E\). coll divide every 20 minutes. A low-end estimate for the division rate of \(E\). coli in human guts is about once every few days. Why is this more realistic? Given these and other uncertainties, how big are the uncertainties in your estimates of \(P_{2}\) and \(P_{3} ?\) (Problem courtesy of Daniel Fisher.)

The molecular clock In eukaryotes, the majority of individual point mutations are thought to be "neutral" and have little or no effect on phenotype. Only a small fraction of the genome codes for proteins and critical DNA regulatory sequences. Even within coding regions, the redundancy of the genetic code is suffcient to render many mutations "synonymous" (that is, they do not change the amino acid, and hence the protein, encoded by the DNA). The slow accumulation of neutral mutations between two populations can be used as a "molecular clock" to estimate the length of time that has passed since the existence of their last common ancestor. In these estimates, it is common to make the simplifying approximations that (1) most mutations are neutral and (2) the rate of accumulation of neutral mutations is just the average point mutation rate per generation (that is, ignoring other kinds of mutations such as deletions, inversions, etc., as well as variations in and correlations among mutations). (a) With a crude estimate of the point mutation rate of humans of \(10^{-8}\) per base pair per generation, what fraction of the possible nucleotide differences would you expect there to be between chimpanzees and humans given that the fossil record and radiochemical dating indicate their lineages diverged about six million years ago? Compare your estimate with the observed result from sequencing of about \(1.5 \%\) (b) Some parasitic organisms (lice are an example) have specialized and co- evolved with humans and chimps separately. A natural hypothesis is that the most recent common ancestor of the human and chimp parasites existed at the same time as that of the human and chimp themselves. How might you test this from DNA sequence data and other information? What are likely to be the largest causes of uncertainty in the estimates? (Problem courtesy of Daniel Fisher.)

Mutual information by another name In the chapter, we introduced the concept of mutual information as the average decrease in the missing information associated with one variable when the value of another variable in known. In terms of probability distributions, this can be written mathematically as \\[I=\sum_{y} p(y)\left[-\sum_{x} p(x) \log _{2} p(x)+\sum_{x} p(x | y) \log _{2} p(x | y)\right]\\] where the expression in square brackets is the difference in missing information, \(S_{x}-S_{x} y,\) associated with probability of \(x, p(x),\) and with probabilify of \(x\) conditioned on \(y, p(x | y)\) Using the relation between the conditional probability \(p(x | y)\) and the joint probability \(p(x, y)\) \\[p(x | y)=\frac{p(x, y)}{p(y)}\\] show that the formula for mutual information given in Equation 21.77 can be used to derive the formula used in the chapter (Equation 21.17 ), namely \\[I=\sum_{x, y} p(x, y) \log _{2}\left[\frac{p(x, y)}{p(x) p(y)}\right]\\].

Comparison of Pax6 and eyeless In this exercise, you will examine the sequences for both Pax and eyeless and consider the differences and similarities between them. First, download the sequences for \(P a \times 6(82069480)\) and eyeless (12643549) from the \(\mathrm{NCB}\) Entrez Protein site using their accession numbers, given in parentheses. Go to the BLAST homepage (www.ncbi.nlm.nih.gov/blast) and, choose "Align two sequences using BLAST (bl2seq)" under the "Specialized BLAST heading. Instead of searching a large database as is typical with BLAST, we will only be aligning two sequences with one another. Paste your sequences for \(P\) ax 6 and eyeless into boxes for Sequence 1 and Sequence 2 and make sure that you choose blastp as the program. When all of this is done, push the Align button. In your BLAST alignments there is a line between "Query" and "Sbjct" that helps guide the eye with the alignment; if "Query" and "Sbjct" agree identically, the matching letter is repeated in the middle; if they do not match exactly but the amino acids are compatible in some sense (a favorable mismatch), then a "+ " is displayed on the middle line to indicate a positive score. Where there is no letter on the middle line indicates an unfavorable mismatch or a gap. The numbers at the beginning and end of the "Query" and "Sbjct" lines tell you the position in the sequence. (a) Choose one of the alignments returned by BLAST and give a tally of the number of (i) identical amino acids; (ii) favorable mismatches; (iii) unfavorable mismatches: (iv) gaps. (b) Give two examples of unfavorable mismatches and two examples of favorable mismatches in your chosen alignment. Based on what you know of the chemistry and structure of the amino acids, why might these amino acid pairs give rise to negative and positive scores, respectively? (c) Choose one unfavorable mismatch pair and one favorable mismatch pair from your chosen alignment. What codons may give rise to each of these amino acids? What is the minimum number of mutations necessary in the DNA to produce this particular unfavorable mismatch? How many DNA mutations would be required to produce the particular favorable mismatch you chose?

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