Chapter 19: Problem 9
For transcription to start, the RNA polymerase bound to the promoter needs to undergo a conformational change to the so-called open complex. The rate of open complex formation is often much smaller than the rates for the polymerase binding and falling off the promoter. Here, we investigate within a simple model how this state of affairs might justify the equilibrium assumption underlying thermodynamic models of gene regulation, namely that the equilibrium probability that the promoter is occupied by the RNA polymerase determines the level of gene expression. (a) Write down the chemical kinetics equation for this situation. Consider three states: RNA polymerase bound nonspecifically on the DNA (N); RNA polymerase bound to the promoter in the closed complex (C); and RNA polymerase bound to the promoter in the open complex (O). To simplify matters, take both the rate for \(\mathrm{N} \rightarrow \mathrm{C}\) and the rate for \(C \rightarrow N\) to be \(k\). Assume that the transition \(C \rightarrow O\) is irreversible, with rate \(\Gamma\) (b) For \(\Gamma=0,\) show that in the steady state there are equal numbers of RNA polymerases in the \(\mathrm{N}\) and \(\mathrm{C}\) states. What is the steady state in the case \(\Gamma \neq 0 ?\) (c) For the case \(\Gamma \neq 0\), show that for times \(1 / k \ll t \ll 1 / \Gamma\), the numbers of RNA polymerases in the \(\mathrm{N}\) and \(\mathrm{C}\) states are equal, as would be expected in equilibrium.
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