Chapter 10: Problem 1
Persistence length and Fourier analysis
In the chapter, we computed the tangent-tangent correlation function for a
polymer, which we modeled as an elastic beam undergoing thermal fluctuations.
The calculation was carried out in the limit of small fluctuations and it led
to an expression for the persistence length in terms of the flexural rigidity
of the polymer. Here we reexamine this problem for a two-dimensional polymer,
but without the assumption of small fluctuations.
(a) For a polymer confined to a plane, the tangent vector \(\mathbf{t}(s)\) can
be written in terms of the polar angle \(\theta(s)\) as \(\mathbf{t}(s)=(\cos
\theta(s), \sin \theta(s)) .\) Rewrite the beam bending energy
Equation \(10.9,\) in terms of the polar angle \(\theta(s)\)
(b) Expand the polar angle \(\theta(s)\) into a Fourier series, taking into
account the boundary conditions \(\theta(0)=0\) and \(\mathrm{d} \theta /
\mathrm{d} s=0\) for \(s=L\). The first boundary condition comes about by
choosing the orientation of the polymer so that the tangent vector at \(s=0\) is
always along the \(x\) -axis. Convince yourself that the second is a consequence
of there being no force acting on the end of the polymer.
(c) Rewrite the bending energy in terms of the Fourier amplitudes
\(\tilde{\theta}_{n},\) introduced in (b), and show that it takes on the form
equivalent to that of many independent harmonic oscillators. Use equipartition
to compute the thermal average of each of the Fourier amplitudes.
(d) Make use of the identity \(\langle\cos X\rangle=\mathrm{e}^{-X^{2} / 2},\)
which holds for a Gaussian distributed random variable \(X,\) to obtain the
equation for the tangent-tangent correlation function, \((\mathbf{t}(s) \cdot
\mathbf{t}(0)\rangle=\mathrm{e}^{-\theta(s)^{2} / 2} .\) Then compute
\(\left\langle\theta(s)^{2}\right)\) by using the
Fourier series representation of \(\theta(s)\) and the average values of the
Fourier amplitudes \(\bar{\theta}_{n}\) obtained in (c). Convince yourself
either by plotting or Fourier analysis that on the
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Short Answer
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Key Concepts
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