Chapter 26: Problem 14
Starting with the definition of the permutation tensor \(\delta_{j_{1} j_{2} \ldots j_{N}}^{i_{1} i_{2} \ldots i_{N}}\), and writing the wedge product in terms of the antisymmetrized tensor product, show that $$ \delta_{j_{1} j_{2} \ldots j_{N}}^{i_{1} i_{2} \ldots i_{N}}=\sum_{\pi} \epsilon_{\pi\left(j_{1}\right) \pi\left(j_{2}\right) \ldots \pi\left(j_{N}\right)} \delta_{\pi\left(j_{1}\right)}^{i_{1}} \delta_{\pi\left(j_{2}\right)}^{i_{2}} \cdots \delta_{\pi\left(j_{N}\right)}^{i_{N}} $$.
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