Chapter 25: Problem 5
Suppose that \(Q\), an element of the group algebra of \(S_{n}\), is given by $$ Q=\sum_{i=1}^{n !} \epsilon_{\pi_{i}} \pi_{i}, \quad \pi_{i} \in S_{n} $$ Show that $$ \pi_{j} Q=\epsilon_{\pi_{j}} Q \quad \text { and } \quad Q^{2}=n ! Q $$.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.