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Calculate the GF of the two-dimensional Laplacian operator appropriate for Neumann \(\mathrm{BCs}\) on the rectangle \(0 \leq x \leq a, 0 \leq y \leq b\).

Short Answer

Expert verified
The Green's Function of the Laplacian operator appropriate for Neumann boundary conditions on the rectangle specified is calculated via the Neumann condition and the method of separation of variables. The resulting function is a product of sinusoidal series in the x and y directions that satisfies both the Laplace equation and the boundary conditions.

Step by step solution

01

Define the Laplacian Operator and Specify the Boundary Conditions

The Laplace operator in two dimensions for a rectangle (0 ≤ x ≤ a, 0 ≤ y ≤ b) can be represented as \(\Delta G = \delta(x-x')\delta(y-y')\), with Neumann boundary conditions. The Neumann condition is defined as \(\frac{\partial G}{\partial n} = 0\), where n is a boundary edge. This condition denotes that the derivative of the function along the boundary equals zero.
02

Separate the Variables

The method of separation of variables implies that the solution can be written as a product of two functions, each depending on one coordinate only. Assume \(G = X(x)Y(y)\). Subsitute \(G\) into the Laplace equation and separate the variables to get two ordinary differential equations.
03

Solve Each Ordinary Differential Equation

Each of the derived differential equations can be solved independently with associated boundary conditions. The solutions will be in the form of sinusoidal series.
04

Construct the Green's Function

The Green's Function can be obtained by multiplying the solutions of the ordinary differential equations together due to the principle of superposition. This will yield the final form of the Green's Function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laplacian Operator
The Laplacian operator, denoted as \(\Delta\), is a powerful tool in mathematics, especially in fields such as physics and engineering. In two dimensions, the Laplacian operator acts on a function \(G(x, y)\) and is given by:
\[\Delta G = \frac{\partial^2 G}{\partial x^2} + \frac{\partial^2 G}{\partial y^2}.\]This expression represents the sum of the second derivatives of the function with respect to each spatial coordinate. The Laplacian measures the rate at which the average value of the function around a point differs from its value at that point, making it essential for understanding concepts like heat flow, electric potential, and diffusion.
In the example of the two-dimensional rectangle provided, the Laplacian is applied over a rectangular domain, and its calculations are tailored to the boundary conditions defined by Neumann conditions.
Neumann Boundary Conditions
Neumann Boundary Conditions are a type of boundary condition used in partial differential equations. They specify that the derivative of the function on the boundary is zero. Mathematically, for a function \(G\), this boundary condition can be expressed as:
\[\frac{\partial G}{\partial n} = 0,\]where \(n\) is the normal to the boundary. This condition implies that there is no flux of whatever quantity \(G\) represents across the boundary. It is often used in physical scenarios where an insulated boundary or a reflecting surface is involved, such as heat insulation or specific wave problems.
In the context of the given problem, Neumann boundary conditions are applied over a rectangular domain, guiding how the Green’s function needs to be constructed so it satisfies these no-flux conditions.
Separation of Variables
Separation of Variables is a technique used to solve differential equations, particularly when the equation may be separated into a product of single-variable functions. For the Laplacian with Green's function calculation, the idea is to assume a solution of the form:
\[G(x, y) = X(x)Y(y).\]By substituting this into our differential equation, derivatives of each function can be separately considered. This transforms the problem into two ordinary differential equations, one in terms of \(x\) and the other in terms of \(y\). Such separation allows each equation to be handled independently, simplifying the complex problem into manageable pieces.
It’s particularly effective in rectangular domains as illustrated in the example, allowing us to explore how the behavior of a function in one direction interplays with that in another.
Ordinary Differential Equations
Ordinary Differential Equations (ODEs) are equations that involve functions of only one variable and their derivatives. After applying the separation of variables, the problem involving the Laplacian operator turns into solving ODEs for each spatial direction. They often take the form:
\[X''(x) = f(x),\quad Y''(y) = g(y)\]and need to incorporate boundary conditions, like the Neumann conditions, to obtain a solution.
In our specific case, the ODEs arise from separating the original partial differential equation into simpler forms under the assumption of separability. The solutions to these equations typically involve trigonometric functions due to the periodic nature of the domain and its conditions, ultimately contributing to the final construction of a Green's Function as outlined in the exercise.

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Most popular questions from this chapter

Calculate the retarded GF for the wave operator in two dimensions and show that it is equal to $$ G_{s}^{(\mathrm{ret})}(\mathbf{r}, t)=\frac{\theta(t)}{2 \pi \sqrt{t^{2}-r^{2}}} $$ Now use this result to obtain the GF for any even number of dimensions: $$ G_{s}^{(\mathrm{ret})}(\mathbf{r}, t)=\frac{\theta(t)}{2 \pi}\left(-\frac{1}{2 \pi r} \frac{\partial}{\partial r}\right)^{n-1}\left[\frac{1}{\sqrt{t^{2}-r^{2}}}\right] \quad \text { for } n=m / 2 . $$

Use the operator separation technique to calculate the Dirichlet GF for the two-dimensional operator \(\nabla^{2}-k^{2}\) on the rectangle \(0 \leq x \leq a, 0 \leq\) \(y \leq b\). Also obtain an eigenfunction expansion for this GF.

Use the operator separation technique to show that (a) the GF for the IIelmholtz operator \(\nabla^{2}+k^{2}\) in three dimensions is $$ G\left(\mathbf{r}, \mathbf{r}^{\prime}\right)=-i k \sum_{l=0}^{\infty} \sum_{m=-l}^{l} j_{l}\left(k r_{<}\right) h_{l}\left(k r_{>}\right) Y_{l m}(\theta, \varphi) Y_{l m}^{*}\left(\theta^{\prime}, \varphi^{\prime}\right), $$ where \(r_{<}\left(r_{>}\right)\) is the smaller (larger) of \(r\) and \(r^{\prime}\) and \(j_{l}\) and \(h_{l}\) are the spherical Bessel and Hankel functions, respectively. No explicit BCs are assumed except that there is regularity at \(r=0\) and that \(G\left(\mathbf{r}, \mathbf{r}^{\prime}\right) \rightarrow\) 0 for \(|\mathbf{r}| \rightarrow \infty\) (b) Obtain the identity $$ \frac{e^{i k\left|\mathbf{r}-\mathbf{r}^{\prime}\right|}}{4 \pi\left|\mathbf{r}-\mathbf{r}^{\prime}\right|}=i k \sum_{l=0}^{\infty} \sum_{m=-l}^{l} j_{l}\left(k r_{<}\right) h_{l}\left(k r_{>}\right) Y_{l m}(\theta, \varphi) Y_{l m}^{*}\left(\theta^{\prime}, \varphi^{\prime}\right) . $$ (c) Derive the plane wave expansion [see Eq. (19.46)] $$ e^{i \mathbf{k} \cdot \mathbf{r}}=4 \pi \sum_{l=0}^{\infty} \sum_{m=-l}^{l} i^{l} j_{l}(k r) Y_{l m}^{*}\left(\theta^{\prime}, \varphi^{\prime}\right) Y_{l m}(\theta, \varphi), $$ where \(\theta^{\prime}\) and \(\varphi^{\prime}\) are assumed to be the angular coordinates of \(\mathbf{k}\). Hint: Let \(\left|\mathbf{r}^{\prime}\right| \rightarrow \infty\), and use $$ \left|\mathbf{r}-\mathbf{r}^{\prime}\right|=\left(r^{\prime 2}+r^{2}-2 \mathbf{r} \cdot \mathbf{r}^{\prime}\right)^{1 / 2} \rightarrow r^{\prime}-\frac{\mathbf{r}^{\prime} \cdot \mathbf{r}}{r^{\prime}} $$ and the asymptotic formula \(h_{l}^{(1)}(z) \rightarrow(1 / z) e^{i[z+(l+1)(\pi / 2)]}\), valid for large \(z\).

Find the GF for the Dirichlet BVP in two dimensions if \(D\) is the UHP and \(\partial D\) is the \(x\) -axis.

Use the operator separation technique to find the three-dimensional Dirichlet GF for the Laplacian in a circular cylinder of radius \(a\) and height \(h\).

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