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Find the GF for the two-dimensional Helmholtz equation \(\left(\nabla^{2}+\right.\) \(\left.k^{2}\right) u=0\) on the rectangle \(0 \leq x \leq a, 0 \leq y \leq b\).

Short Answer

Expert verified
The step-by-step process of calculating the Green's function for the given Helmholtz equation involves the separation of variables, obtaining a system of two ordinary differential equations (ODEs) by simplifying the given equation, and finally implementing boundary conditions. The exact form of the Green's function is complicated and it depends on the specific boundary conditions.

Step by step solution

01

Separate Variables

Assume a solution of the form \(u(x, y) = X(x)Y(y)\), this is a method called separation of variables. Substitute for \(u(x, y)\) in the given Helmholtz equation and divide the entire equation by \(u(x, y)\) to separate the variables.
02

Obtain a System of Two Ordinary Differential Equations (ODEs)

After the replacement in the first step, the Helmholtz equation is separated into two ordinary differential equations. Then, the general solution to these new ODEs can be obtained. These solutions are based on the realm of complex numbers and knowledge of calculus. From the solutions of the ODEs, solutions for \(X(x)\) and \(Y(y)\) are obtained.
03

Implement Boundary Conditions

Once the forms for \(X(x)\) and \(Y(y)\) are determined, it is time to apply the boundary conditions given by the rectangle \(0 \leq x \leq a, 0 \leq y \leq b\). After applying the boundary conditions, derive the quantization condition, and hence the final form of the Green's function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separation of Variables
The separation of variables is a mathematical technique used to simplify partial differential equations (PDEs) like the Helmholtz equation. The idea is to assume that a complex function can be written as the product of simpler, single-variable functions. In the problem, this means expressing the function as \(u(x, y) = X(x)Y(y)\). By substituting this product into the Helmholtz equation, it becomes possible to split it into two separate equations, each depending on a single variable. This approach significantly reduces the complexity of solving PDEs. It enables us to tackle each simplified ordinary differential equation (ODE) independently rather than facing the full complexity of the original PDE all at once. This method is powerful in mathematical physics and engineering, especially for problems with well-defined boundary conditions.
Ordinary Differential Equations
Once the variables are separated, the Helmholtz equation transforms into two ordinary differential equations (ODEs). ODEs are equations involving functions of one independent variable and their derivatives. Solving these ODEs is crucial in obtaining solutions for \(X(x)\) and \(Y(y)\). The ODEs arising from the separated Helmholtz equation typically require solutions that can handle complex numbers and engage fundamental calculus operations.
  • Typically, you find a general solution which incorporates constants, both derived from boundary conditions.
  • The type of ODEs dictates the solution method: they could resemble standard forms like harmonic oscillators or exponentials depending on the nature of the problem.
By solving these, we take a significant step toward solving the original partial differential equation.
Boundary Conditions
Boundary conditions are constraints necessary for a unique solution of a differential equation. In this exercise, we apply these to the boundaries of a rectangle defined by \(0 \leq x \leq a, 0 \leq y \leq b\). They ensure the solution within the region behaves correctly at its borders, adhering to physical or theoretical conditions of the problem. By implementing boundary conditions, unknown constants from the ODE solutions are determined.
  • Once the boundary conditions are applied, one derives a quantization condition, limiting the possible solutions to those satisfying the boundary requirements.
  • This leads to discrete solutions for the involved parameters, facilitating the extraction of the final form of the Green's function.
The effective application of boundary conditions is vital, as it ensures that our solution is applicable to the problem's physical context.
Green's Function
A Green's function is a powerful tool for solving inhomogeneous differential equations subject to specific boundary conditions. In the context of the Helmholtz equation, it's utilized to express the solution over the defined domain of a rectangle, creating a bridge between the differential equation and its imposed boundary conditions.
  • The Green's function encapsulates the effects of the source terms in the equations with the boundary constraints.
  • It establishes a linkage for solving multiple sources by superimposing solutions, making it invaluable for varied applications in physics and engineering.
In practical terms, once the Green's function is derived, it can be used to determine how the solution \(u(x, y)\) responds to different inputs and constraints, essentially simplifying the problem of finding a specific solution to a more general form.

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Most popular questions from this chapter

For the Helmholtz operator \(\nabla^{2}-k^{2}\) in the half-space \(z \geq 0\), find the three-dimensional Dirichlet GF.

Use the operator separation technique to show that (a) the GF for the IIelmholtz operator \(\nabla^{2}+k^{2}\) in three dimensions is $$ G\left(\mathbf{r}, \mathbf{r}^{\prime}\right)=-i k \sum_{l=0}^{\infty} \sum_{m=-l}^{l} j_{l}\left(k r_{<}\right) h_{l}\left(k r_{>}\right) Y_{l m}(\theta, \varphi) Y_{l m}^{*}\left(\theta^{\prime}, \varphi^{\prime}\right), $$ where \(r_{<}\left(r_{>}\right)\) is the smaller (larger) of \(r\) and \(r^{\prime}\) and \(j_{l}\) and \(h_{l}\) are the spherical Bessel and Hankel functions, respectively. No explicit BCs are assumed except that there is regularity at \(r=0\) and that \(G\left(\mathbf{r}, \mathbf{r}^{\prime}\right) \rightarrow\) 0 for \(|\mathbf{r}| \rightarrow \infty\) (b) Obtain the identity $$ \frac{e^{i k\left|\mathbf{r}-\mathbf{r}^{\prime}\right|}}{4 \pi\left|\mathbf{r}-\mathbf{r}^{\prime}\right|}=i k \sum_{l=0}^{\infty} \sum_{m=-l}^{l} j_{l}\left(k r_{<}\right) h_{l}\left(k r_{>}\right) Y_{l m}(\theta, \varphi) Y_{l m}^{*}\left(\theta^{\prime}, \varphi^{\prime}\right) . $$ (c) Derive the plane wave expansion [see Eq. (19.46)] $$ e^{i \mathbf{k} \cdot \mathbf{r}}=4 \pi \sum_{l=0}^{\infty} \sum_{m=-l}^{l} i^{l} j_{l}(k r) Y_{l m}^{*}\left(\theta^{\prime}, \varphi^{\prime}\right) Y_{l m}(\theta, \varphi), $$ where \(\theta^{\prime}\) and \(\varphi^{\prime}\) are assumed to be the angular coordinates of \(\mathbf{k}\). Hint: Let \(\left|\mathbf{r}^{\prime}\right| \rightarrow \infty\), and use $$ \left|\mathbf{r}-\mathbf{r}^{\prime}\right|=\left(r^{\prime 2}+r^{2}-2 \mathbf{r} \cdot \mathbf{r}^{\prime}\right)^{1 / 2} \rightarrow r^{\prime}-\frac{\mathbf{r}^{\prime} \cdot \mathbf{r}}{r^{\prime}} $$ and the asymptotic formula \(h_{l}^{(1)}(z) \rightarrow(1 / z) e^{i[z+(l+1)(\pi / 2)]}\), valid for large \(z\).

Consider a rectangular box with sides \(a, b\), and \(c\) located in the first octant with one corner at the origin. Let \(D\) denote the inside of this box. (a) Show that zero cannot be an eigenvalue of the Laplacian operator with the Dirichlet \(\mathrm{BCs}\) on \(\partial D\). (b) Find the GF for this Dirichlet BVP.

Show that the diffusion operator satisfies $$ \mathbf{L}_{\mathbf{x}, t} G(\mathbf{x}, \mathbf{y} ; t-\tau)=\delta(\mathbf{x}-\mathbf{y}) \delta(t-\tau) . $$ Hint: Use $$ \frac{\partial \theta}{\partial t}(t-\tau)=\delta(t-\tau) $$

Calculate the GF of the two-dimensional Laplacian operator appropriate for Neumann \(\mathrm{BCs}\) on the rectangle \(0 \leq x \leq a, 0 \leq y \leq b\).

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