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If you try to throw a basketball into a basket, the likelihood of succeeding depends on the size of the basket. It is more likely that you will get the ball into the basket if the basket is bigger. In your own words, explain how this analogy applies to the idea that the likelihood of crossing over is greater when two genes are far apart than when they are close together.

Short Answer

Expert verified
The basketball and genes analogy applies as follows: Just as you have a better chance of making a shot with a larger basketball hoop, there is a greater chance for crossing over to occur when genes are far apart. This is because when genes are distant, there is a greater variety of points where crossing over can occur, similar to how a larger hoop provides a larger 'target' for the ball.

Step by step solution

01

Understand the analogy

First, it is paramount to understand the initial analogy given: scoring a basket is easier when the basket is bigger. This is because there is more space for the ball to enter, making it a higher probability event.
02

Apply the analogy

In genetics, 'crossing over' refers to the process where two chromosomes swap sections of their DNA - effectively, genes get mixed, creating genetic diversity. If two genes are close together on the chromosome, they're like a small basket - it's less likely for a 'hit' (or a swap/crossover) to occur. However, when the genes are far apart, it's like a large basket - there's a greater chance of a 'hit' happening. In both cases, the larger the 'target,' the higher the probability of hitting it.
03

Finalize and communicate the analogy

To put it together, when genes are far apart on a chromosome, the 'basket' for genetic recombination is larger. More variations of gene combinations can occur, leading to a higher likelihood of crossing over taking place. Similarly, a larger basketball hoop allows for more successful shots due to the increased margin for error. The 'shots' in genetics are the processes leading to recombination, and the larger 'hoop' represents the larger gene-to-gene distance which increases the likelihood of a successful 'shot,' or recombination.

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Most popular questions from this chapter

Researchers have discovered that some regions of chromosomes are much more likely than others to cross over. We might call such a region a "hot spot" for crossing over. Let's suppose that two genes, gene \(A\) and gene \(B\), are \(5,000,000 \mathrm{bp}\) apart on the same chromosome. Genes \(A\) and \(B\) are in a hot spot for crossing over. Two other genes, let's call them gene \(C\) and gene \(D\), are also \(5,000,000 \mathrm{bp}\) apart but are not in a hot spot for recombination. If we conducted two-factor crosses to compute the map distance between genes \(A\) and \(B\) and other two-factor crosses to compute the map distance between genes \(C\) and \(D\), would the calculated map distance between \(A\) and \(B\) be the same as that between \(C\) and \(D\) ? Explain.

What is mitotic recombination? A heterozygous individual \((B b)\) with brown eyes has one eye with a small patch of blue. Provide two or more explanations for how the blue patch may have occurred.

When true-breeding mice with brown fur and short tails (BBtt) were crossed to true-breeding mice with white fur and long tails (bbTT), all of the \(\mathrm{F}_{1}\) offspring had brown fur and long tails. The \(\mathrm{F}_{1}\) offspring were crossed to mice with white fur and short tails. What are the possible phenotypes of the \(\mathrm{F}_{2}\) offspring? Which \(\mathrm{F}_{2}\) offspring are recombinant, and which are nonrecombinant? What are the ratios of phenotypes of the \(\mathrm{F}_{2}\) offspring if independent assortment is taking place? How are the ratios affected by linkage?

Mitotic recombination can occasionally produce a twin spot. Let's suppose an animal species is heterozygous for two genes that govern fur color and length: one gene affects pigmentation, with dark pigmentation \((A)\) dominant to albino \((a)\); the other gene affects hair length, with long hair \((L)\) dominant to short hair \((I)\). The two genes are linked on the same chromosome. Let's assume an animal of this species is \(A a L l ; A\) is linked to \(I\), and \(a\) is linked to \(L\). Draw the chromosomes labeled with these alleles, and explain how mitotic recombination could produce a twin spot with one spot having albino pigmentation and long fur and the other having dark pigmentation and short fur.

In most two-factor crosses involving linked genes, we cannot tell if a double crossover between the two genes has occurred because the offspring will inherit the nonrecombinant pattern of alleles. How does the inability to detect double crossovers affect the calculation of map distance? Is map distance underestimated or overestimated because of our inability to detect double crossovers? Explain your answer.

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