Question

If a diploid cell contains six chromosomes (i.e., three per set), how many possible random arrangements of homologs could occur during metaphase of meiosis I?

Short answer

The possible random arrangements of homologs during metaphase of meiosis I are 8.

Step-by-step solution

Identify the number of homologous pairs

In a diploid cell, chromosomes come in pairs known as homologous pairs. The problem provides that the cell contains six chromosomes. Half of these make up one set. Therefore we have 3 homologous pairs, i.e., \(n = 3\).

Apply the formula for the total possible arrangements of homologous chromosomes

We know the formula to calculate the possible random arrangements of homologs during metaphase of meiosis I is \(2^n\). By plugging our \(n = 3\) into the formula, we get: \(2^3\)

Solve the equation

The calculation \(2^3 = 2*2*2 = 8\). Therefore, there are 8 possible random arrangements of homologous chromosomes during metaphase of meiosis I.