Chapter 7: Problem 157
The gene \(\mathrm{r}\), for rosy eyes, is 12 map units away from the gene \(k\), for kidney-shaped eyes. Both of these genes are recessive to their wild-type alleles. If a heterozygous wild-type fly, resulting from a cross between a homozygous wild-type fly and a fly with rosy, kidney-shaped eyes, is crossed to a fly with rosy, kidney-shaped eyes, what will be the types of gametes and the frequencies of each?
Short Answer
Step by step solution
Determine the phenotypes of each parent fly
Determine the genotypes of each parent fly
Determine the possible gametes that can be produced by each parent fly
Determine the frequencies of each gamete
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Map Units in Genetics
The exercise illustrates this by discussing two genes that are 12 map units apart, which means there is a 12% chance of recombination occurring between them. This relatively short distance indicates that these genes are fairly close to one another on the chromosome and thus have a higher likelihood of being inherited together unless crossing over splits them apart. Consequently, when calculating the types and frequencies of gametes in genetic crosses, map unit distances are crucial for determining the proportion of recombinant and parental gametes produced.
Alleles and Genotypes
In the given exercise, the alleles 'R' and 'K' for eye color and shape, respectively, are dominant, while 'r' and 'k' are their recessive counterparts. The genotype is the set of alleles an individual carries. For instance, 'RrKk' is the genotype of a heterozygous wild-type fly, indicating it has both dominant and recessive alleles for eye color and shape. Genotypes are crucial because they determine phenotypes—the observable characteristics. When generating the types of gametes for genetic crosses, researchers look at the genotype to predict potential genetic outcomes, like the gametes 'RK', 'Rk', 'rK', and 'rk' derived in the steps of the exercise.