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Hemophilia, a genetic blood disorder, is caused by a recessive sex-linked gene. A phenotypically normal couple had a son with hemophilia. What is the probability that their next child, if a girl, would also have hemophilia?

Short Answer

Expert verified
The probability that their next child, if a girl, would also have hemophilia is 25%.

Step by step solution

01

Identifying the parents' genotypes

In a sex-linked gene, the hemophilia gene in question is located in the X chromosome. Males have one X and one Y chromosome (XY), whereas females have two X chromosomes (XX). Since the father is phenotypically normal, he must have no faulty hemophilia gene in his X chromosome: XY The woman has a normal phenotype too, but her son does have hemophilia. That means she is a carrier, and her genotype is XhX, where 'Xh' denotes the recessive hemophilia gene. So the parents' genotypes are: Mother: XhX Father: XY
02

Setting up a Punnett square

A Punnett square is a diagram that is used to predict the probability and ratio of genotypes of offspring from a particular cross or breeding event. We will set up a Punnett square to represent the possible genotypes of the next child. X Y _______________ Xh | XhX | XhY | _________ X | XX | XY | _________
03

Interpreting the Punnett square

The Punnett square now shows us the genotypes of the possible offspring from this couple: - XhX: female child with a carrier mother (25% chance) - XhY: male child with hemophilia (25% chance) - XX: normal female child (25% chance) - XY: normal male child (25% chance)
04

Calculating the probability

The exercise asks for the probability of a girl with hemophilia. There is only one possible genotype for this scenario, which is XhX (carrier mother). The chance of having a girl with such genotype is 25% (1 out of 4 possibilities in the Punnett square). So, the probability that their next child, if a girl, would also have hemophilia is 25%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

hemophilia
Hemophilia is a genetic disorder where blood doesn't clot properly. This can lead to excessive bleeding from even minor injuries. The condition is primarily due to a defect in one of the genes located on the X chromosome, which plays a crucial role in blood clotting.

Since hemophilia is linked to this specific chromosome, it often affects males more frequently. Men have just one X chromosome, so if it's defective, they will likely exhibit symptoms of hemophilia. In contrast, females have two X chromosomes. This means they can carry the defective gene on just one chromosome and not show symptoms if the other X chromosome is normal.

However, females can still be carriers of the disorder and pass it on to their children, which is an important aspect of understanding genetic inheritance. Being aware of family history can help in identifying those who might be carriers of hemophilia.
sex-linked genes
Sex-linked genes are those located on the sex chromosomes, specifically the X or Y chromosomes in humans. These chromosomes determine our biological sex, with females having two X chromosomes (XX) and males having one X and one Y chromosome (XY).

When a gene associated with a particular condition is found on these chromosomes, it is termed a "sex-linked gene." The majority of sex-linked genes are found on the X chromosome since it carries more genes than the Y chromosome. Disorders like hemophilia and color blindness are examples of conditions caused by mutations in these genes.

It's also important to note that males are more likely than females to express X-linked recessive disorders. This is because they possess only one X chromosome. Thus, any mutation that occurs there can result in the full expression of the disorder.
Punnett square
The Punnett square is a simple and widely used tool in genetics to predict the genotypes of offspring from a genetic cross. Named after Reginald C. Punnett, this diagram helps clarify the probability of inheriting specific traits.

To create a Punnett square, you draw a grid and input the gametes of each parent along the top and side of the square. By filling in the grid, you can see all possible combinations of parental alleles and thus the potential genotypes of their offspring.

In our hemophilia example, the mother is a carrier (XhX) while the father has normal wild-type alleles (XY). The Punnett square shows the likelihood of each child inheriting a particular genotype. This makes it a vital tool in analyzing the probability of inheritance patterns for various genetic disorders.
recessive genes
Recessive genes are those whose traits are not expressed unless two copies of the gene are present. A single dominant allele can mask the presence of a recessive gene. In the context of genetic disorders, if a disorder is caused by a recessive gene, then an individual must inherit two copies of that faulty gene to display the disorder.

In the case of hemophilia, the gene responsible is recessive and located on the X chromosome. While males are directly impacted if they inherit this gene because they have only one X chromosome, females generally require two copies of the recessive gene (one on each X chromosome) to exhibit the symptoms.

This mechanism of genetic inheritance explains why carriers exist. Carriers have one normal and one affected gene, typically not displaying symptoms but capable of passing the recessive gene to their children. Understanding how recessive genes work helps unravel the complexities of genetic disorders and inheritance.

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Most popular questions from this chapter

In turkeys, the gene for short wattle \((\ell)\) is \(\mathrm{X}\) -linked recessive. Its wild-type allele (L) is responsible for producing a long wattle. In I turkeys, like in all birds, the female is the heterogametic sex, possessing an \(\mathrm{X}\) and a \(\mathrm{Y}\) chromosome. The male has two \(\mathrm{X}\) chromosomes. The sex of the female can be reversed to male if the one functional ovary is destroyed or removed. Assuming that such a reversal can yield a fertile male, what will be the phenotypic ratio of a cross between a short-wattled reversed male and a long-wattled female?

In Drosophila melanogaster, the gene for white eyes, \(\mathrm{w}\), is recessive and X-linked. Red eyes result from the wild-type allele at this locus. (a) On chromosomes, symbolize the genotypes of a white-eyed male, a red-eyed female (both possible types), and a white-eyed female. (b) Diagram a cross between a homozygous red-eyed female and white-eyed male. Carry this to the \(\mathrm{F}_{2}\) generation and give phenotype ratios for each sex. (c) Show a cross between an \(\mathrm{F}_{1}\) female and white-eyed male. Give phenotype ratios. (d) Show a cross between an \(\mathrm{F}_{1}\) female and wild-type male. Also give ratios.

A girl is a hemophiliac. (a) What are the possible genotypes and phenotypes of her parents? (b) Assuming that her mother is normal, what were this girl's chances of being born with the disease? (c) Several cases of hemophilia in girls have been reported within a small region in England where there is often close intermarriage. Explain this high frequency of hemophilia in girls.

Even though sex determination does not appear to be controlled by the chromosomal method in some dioecious organisms, it is still gene determined. Explain.

Explain the mode of inheritance for color blindness.

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