Chapter 11: Problem 302
Do histones control gene activity?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 11: Problem 302
Do histones control gene activity?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeHow can the expression of eukaryotic genes be regulated?
How does the measurement of enzymatic activity help to detect galactosemia?
Explain how gene expression is regulated during \(\lambda\) phage infection.
Partial diploids can be produced in the bacterium \(\mathrm{E}\). coli for the lac operon. As a consequence, some mutations can be bypassed in terms of their disruption of the operon by production of the partial diploids with wild-type alleles at the sites of mutation. In each case the wild-type allele is dominant to its mutant homologue. Determine for each of the following partial diploids whether enzyme production will result constitutively or inducibly (normally) when the inducer molecule is introduced: (a) \(\underline{i}^{\pm} \mathrm{o}^{\pm} \underline{z}^{-}-\mathrm{y}^{-} \mathrm{a}=\) \(\mathrm{i}^{+} o^{c} \mathrm{z}^{+} \mathrm{y}^{+} \mathrm{a}^{+}\) (b) \(\underline{i}=\underline{o}^{\pm} \underline{z}^{\pm}-\mathrm{y}^{\pm} \underline{a}^{\pm}\) \(\mathrm{i}^{+} \mathrm{o}^{+} \mathrm{z}^{+} \mathrm{y}^{-} \mathrm{a}^{-}\) (c) \(\underline{i}^{\pm} \underline{o}^{\mathrm{c}} \underline{z^{\pm}}-\mathrm{y}=\underline{\mathrm{a}}=\) \(i^{-} o^{+} z^{-} y^{-} a^{-}\)
Given the lactose operon in the bacterium Escherichia coli: Where \(\quad \mathrm{i}=\) regulator gene \(\mathrm{p}=\) promoter site \(o=\) operator site \(z=\) structural gene for \(\beta\) -galactosidase \(\mathrm{y}=\) structural gene for \(\beta\) -galactoside permease \(\mathrm{a}=\) structural gene for thiogalactoside transacetylase Assuming that the inducer molecule, lactose, is present, what would be the result in terms of enzyme synthesis if the following mutational events took place: (a) mutation of i such that a defective repressor results that does not recognize 0 (b) mutation of i such that a "superrepressor" results that does not recognize lactose (c) mutation of o such that the repressor will not recognize \(\mathrm{O}\) (d) mutation of \(\mathrm{p}\).
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