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What is the genetic basis for phenylketonuria (PKU)? When are heterozygotes for PKU more likely to have abnormalities?

Short Answer

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The genetic basis for phenylketonuria (PKU) is a mutation in the PAH gene located on chromosome 12, which leads to a deficiency in the enzyme phenylalanine hydroxylase. PKU is an autosomal recessive disorder, meaning both parents must carry a copy of the mutated gene for a child to inherit the disorder. Heterozygotes, who carry one mutated and one normal PAH gene, typically do not exhibit symptoms but can pass the mutation to their offspring. However, they may experience abnormalities under extreme dietary conditions, high phenylalanine intake, or a temporary decrease in PAH enzyme activity triggered by stress or illness.

Step by step solution

01

Understanding phenylketonuria (PKU)

Phenylketonuria (PKU) is an inherited disorder caused by a deficiency in the enzyme phenylalanine hydroxylase (PAH). The main function of PAH is to break down the amino acid phenylalanine. Without this enzyme, phenylalanine accumulates in the body, leading to various health problems such as intellectual disability and developmental delays.
02

The genetic basis for PKU

PKU is an autosomal recessive disorder. This means that both parents must carry a copy of the mutated PAH gene (allele) for their child to inherit PKU. If both parents are carriers of the mutated gene, there is a 25% chance the child will inherit PKU, a 50% chance the child will be a carrier (heterozygote), and a 25% chance the child will not inherit the mutated gene at all. The mutated PAH gene is located on chromosome 12.
03

Understanding heterozygotes for PKU

Heterozygotes for PKU are individuals who carry only one copy of the mutated PAH gene and one normal copy. These individuals are carriers of the PKU mutated gene but do not typically exhibit symptoms of the disorder themselves. However, they can pass the mutated gene to their offspring.
04

Occurrences of abnormalities in heterozygotes for PKU

While heterozygotes for PKU do not usually show symptoms of the disorder, there are circumstances in which they may experience abnormalities. One of these circumstances is when they are exposed to extreme dietary conditions, such as consuming large amounts of phenylalanine. Another situation is when they have a temporary decrease in PAH enzyme activity caused by stress, illness, or other factors. In these cases, the accumulation of phenylalanine can lead to health issues similar to those seen in individuals with PKU. In conclusion, phenylketonuria is an autosomal recessive disorder caused by mutations in the PAH gene. Heterozygotes for PKU are more likely to experience abnormalities in situations where they consume high levels of phenylalanine or have a temporary reduction in PAH enzyme activity due to stress or illness.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Autosomal Recessive Disorder
Phenylketonuria (PKU) is classified as an autosomal recessive disorder. In simple terms, this means that the disorder is inherited when both parents pass on a copy of the mutated gene responsible for PKU to their child.
For a child to have PKU, they must inherit two mutated PAH genes, one from each parent.
  • If a child receives one normal PAH gene and one mutated gene, they won't show symptoms of PKU. Instead, they will be carriers.
  • If both parents are carriers, there is a 1 in 4 chance that their child will have PKU.
  • There is also a 1 in 2 chance that the child will be a carrier like the parents.
This pattern of inheritance is characteristic of many genetic disorders and plays a crucial role in genetic counseling.
PAH Gene
The PAH gene provides the instructions for making an enzyme known as phenylalanine hydroxylase. This enzyme is essential because it helps in breaking down the amino acid phenylalanine, which is found in many protein-rich foods.
However, mutations in the PAH gene disrupt the production of this enzyme, leading to the symptoms associated with PKU.
  • People with PKU have a defective version of this gene.
  • The lack of the enzyme results in excess phenylalanine, which can harm brain development and function if not managed through diet.
Understanding the PAH gene is vital for managing PKU, as treatment often involves special diets to limit phenylalanine intake.
Heterozygotes
Heterozygotes are individuals who carry one normal copy of a gene and one mutated copy. In the context of PKU, heterozygotes have one healthy PAH gene and one mutated PAH gene. This genetic makeup means that they typically do not show symptoms of PKU.
They are considered carriers since they can pass the mutated gene to their children.
  • Heterozygotes generally have enough functioning enzyme to prevent phenylalanine from building up.
  • However, under certain circumstances, like poor diet or stress, they might experience minor symptoms.
Thus, even though they seem unaffected, being aware of their carrier status is key for family planning and genetic counseling.
Enzyme Phenylalanine Hydroxylase
Phenylalanine hydroxylase is a critical enzyme in the human body, responsible for converting the amino acid phenylalanine into tyrosine. This process is crucial for normal health.
Without proper enzyme function, phenylalanine accumulates, which can be toxic to the brain.
  • This enzyme is produced based on the instructions from the PAH gene.
  • Deficiencies in this enzyme are the cornerstone of PKU's development.
  • Those diagnosed with PKU often follow a strict diet to accommodate the lack of enzyme activity.
Maintaining balanced levels of phenylalanine through diet can help prevent the adverse effects associated with PKU.
Chromosome 12
The PAH gene is located on chromosome 12, one of the 23 pairs of chromosomes in each human cell. Chromosome 12 is especially important because it holds many genes, including those involved in skin growth and development of the reproductive system.
In this context, the PAH gene's location is crucial for geneticists when diagnosing and researching PKU as an autosomal recessive disorder.
  • Chromosomal analysis can help identify mutations in the PAH gene.
  • Understanding this can aid in developing therapies and managing PKU.
Through the study of chromosome 12, scientists continue to gain insights into genetic disorders like PKU, paving the way for improved treatments and understanding of genetic influences on health.

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Most popular questions from this chapter

Partial diploids can be produced in the bacterium \(\mathrm{E}\). coli for the lac operon. As a consequence, some mutations can be bypassed in terms of their disruption of the operon by production of the partial diploids with wild-type alleles at the sites of mutation. In each case the wild-type allele is dominant to its mutant homologue. Determine for each of the following partial diploids whether enzyme production will result constitutively or inducibly (normally) when the inducer molecule is introduced: (a) \(\underline{i}^{\pm} \mathrm{o}^{\pm} \underline{z}^{-}-\mathrm{y}^{-} \mathrm{a}=\) \(\mathrm{i}^{+} o^{c} \mathrm{z}^{+} \mathrm{y}^{+} \mathrm{a}^{+}\) (b) \(\underline{i}=\underline{o}^{\pm} \underline{z}^{\pm}-\mathrm{y}^{\pm} \underline{a}^{\pm}\) \(\mathrm{i}^{+} \mathrm{o}^{+} \mathrm{z}^{+} \mathrm{y}^{-} \mathrm{a}^{-}\) (c) \(\underline{i}^{\pm} \underline{o}^{\mathrm{c}} \underline{z^{\pm}}-\mathrm{y}=\underline{\mathrm{a}}=\) \(i^{-} o^{+} z^{-} y^{-} a^{-}\)

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Given the lactose operon in the bacterium Escherichia coli: Where \(\quad \mathrm{i}=\) regulator gene \(\mathrm{p}=\) promoter site \(o=\) operator site \(z=\) structural gene for \(\beta\) -galactosidase \(\mathrm{y}=\) structural gene for \(\beta\) -galactoside permease \(\mathrm{a}=\) structural gene for thiogalactoside transacetylase Assuming that the inducer molecule, lactose, is present, what would be the result in terms of enzyme synthesis if the following mutational events took place: (a) mutation of i such that a defective repressor results that does not recognize 0 (b) mutation of i such that a "superrepressor" results that does not recognize lactose (c) mutation of o such that the repressor will not recognize \(\mathrm{O}\) (d) mutation of \(\mathrm{p}\).

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