Chapter 11: Problem 290
Tay-Sachs disease is an inborn error of metabolism. How can heterozygotes be detected?
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These are the key concepts you need to understand to accurately answer the question.
Chapter 11: Problem 290
Tay-Sachs disease is an inborn error of metabolism. How can heterozygotes be detected?
These are the key concepts you need to understand to accurately answer the question.
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Partial diploids can be produced in the bacterium \(\mathrm{E}\). coli for the lac operon. As a consequence, some mutations can be bypassed in terms of their disruption of the operon by production of the partial diploids with wild-type alleles at the sites of mutation. In each case the wild-type allele is dominant to its mutant homologue. Determine for each of the following partial diploids whether enzyme production will result constitutively or inducibly (normally) when the inducer molecule is introduced: (a) \(\underline{i}^{\pm} \mathrm{o}^{\pm} \underline{z}^{-}-\mathrm{y}^{-} \mathrm{a}=\) \(\mathrm{i}^{+} o^{c} \mathrm{z}^{+} \mathrm{y}^{+} \mathrm{a}^{+}\) (b) \(\underline{i}=\underline{o}^{\pm} \underline{z}^{\pm}-\mathrm{y}^{\pm} \underline{a}^{\pm}\) \(\mathrm{i}^{+} \mathrm{o}^{+} \mathrm{z}^{+} \mathrm{y}^{-} \mathrm{a}^{-}\) (c) \(\underline{i}^{\pm} \underline{o}^{\mathrm{c}} \underline{z^{\pm}}-\mathrm{y}=\underline{\mathrm{a}}=\) \(i^{-} o^{+} z^{-} y^{-} a^{-}\)
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