Chapter 1: Problem 19
Assume that the diploid number of chromosomes in a cell is \(2 \mathrm{n}=8\). Suppose that in undergoing meiosis one pair of homologs fails to disjoin at the first meiotic division and both homologs of the pair proceed to the same pole. (a) How many chromatids would be present in each daughter cell resulting from meiosis I? (b) If the second meiotic division divides all the sister chromatids, how many chromatids would be present in each of the four resulting gametes?
Short Answer
Step by step solution
Key Concepts
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