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Compare and contrast the actions of an allosteric effector, a competitive enzyme inhibitor, and a non-competitive inhibitor.

Short Answer

Expert verified

Allosteric effectors bind to locations on the enzyme other than the active site, changing its conformation slightly to enhance or decrease substrate affinity. However, competitive and non-competitive inhibitors bind directly to the enzyme's active site to prevent substrate binding.

Step by step solution

01

Competitive inhibitor

A chemical that binds to the active site of an enzyme and inhibits (prevents) a process by having a structure similar to that of the enzyme's substrate is known as a competitive inhibitor.

Competitive enzyme inhibitors slow down enzyme function and prevent the enzyme from catalyzing the process by acting at the active site and preventing substrate binding. By providing an extra substrate, the effect of a competitive inhibitor can be mitigated.

02

Non-competitive inhibitor

Non-competitive enzyme inhibitors work by interfering with substrate binding at a place other than the active site on the enzyme molecule.

Because the structure of the enzyme is permanently altered and the substrate will not attach to the active site, the effect of a non-competitive inhibitor cannot be undone by adding more substrate.

03

Allosteric inhibitor

A conformational shift in the active site, which alters its shape and decreases the enzyme's affinity for its substrate, is known as an allosteric inhibitor. Allosteric effectors bind to enzymes to provide allosteric effects.

Allosteric effects that are positive lead the enzyme to be activated, which means that its activity is increased. Negative allosteric effects reduce the enzyme's activity by inhibiting it. Allosteric effectors attach to enzymes and cause them to go into an inactive state.

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Most popular questions from this chapter

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Summarize the purpose of phases I through III of a clinical trial.

Explain the structural basis for cooperative substrate binding and allosteric control in ATCase.

You are constructing a velocity versus [substrate] curve for an enzyme whose KM is believed to be about 2 ฮผM. The enzyme concentration is 200 nM and the substrate concentrations range from 0.1 ฮผM to 10 ฮผM. What is wrong with this experimental setup and how could you fix it?

Sphingosine-1-phosphate (SIP) is important for cell survival. The synthesis of SIP from sphingosine and ATP is catalyzed by the enzyme sphingosine kinase. An understanding of the kinetics of the sphingosine kinase reaction may be important in the development of drugs to treat cancer. The velocity of the sphingosine kinase reaction was measured in the presence and absence of threo-sphingosine, a stereoisomer of sphingosine that inhibits the enzyme. The results are shown below.

[Sphingosine]

(๐›M)

vโ‚’ (mg minโปยน)

(no inhibitor)

vโ‚’ (mg minโปยน)

(with threo-sphingosine)

2.5

32.3

8.5

3.5

40

11.5

5

50.8

14.6

10

72

25.4

20

87.7

43.9

50

115.4

70.8

Construct a Lineweaver-Burk plot to answer the following questions:

(a) What are the apparent KM and Vmax values in the presence and absence of the inhibitor?

(b) What kind of an inhibitor is threo-sphingosine? Explain.

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