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Are sister chromatid exchanges effective in producing genetic variability in an individual? in the offspring of individuals?

Short Answer

Expert verified
Answer: Sister chromatid exchanges play a limited role in producing genetic variability in the offspring of individuals by influencing recombination during meiosis. However, they have a minimal impact on genetic variability within individuals, as the exchanges usually occur between identical chromatids.

Step by step solution

01

Understanding sister chromatid exchange

Sister chromatid exchange refers to a process where two replicated chromosomes (sister chromatids) within a cell exchange genetic material during mitosis or meiosis. This process can be initiated by cellular events such as DNA recombination or DNA repair.
02

Role of sister chromatid exchange in genetic variability within an individual

Sister chromatid exchange does not create any new genetic information, but it can lead to the reshuffling of existing genetic material within the chromosomes. However, sister chromatid exchanges usually occur between sister chromatids (which are identical copies of the same chromosome) resulting in no significant genetic variability. In most cases, the sister chromatid exchange has little or no impact on the genetic variability within an individual.
03

Role of sister chromatid exchange in genetic variability in the offspring of individuals

During meiosis, sister chromatid exchanges can have a role in genetic variability. Meiosis involves homologous chromosome pairing and recombination, leading to the production of genetically unique gametes. Although sister chromatid exchanges themselves do not introduce new genetic variability, they can influence the outcome of recombination events between homologous chromosomes, which contributes to genetic variability in offspring. However, the overall contribution of sister chromatid exchanges to genetic variability in offspring is limited compared to other mechanisms, such as crossing over between homologous chromosomes.
04

Conclusion

In conclusion, sister chromatid exchanges can play a limited role in producing genetic variability in the offspring of individuals by influencing recombination during meiosis. However, they have a minimal impact on genetic variability within individuals, as the exchanges usually occur between identical chromatids.

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Most popular questions from this chapter

Review the Chapter Concepts list on page \(136 .\) Most of these center on the process of crossing over between linked genes. Write a short essay that discusses how crossing over can be detected and how the resultant data provide the basis of chromosome mapping.

In Drosophila, a cross was made between females expressing the three X-linked recessive traits, scute bristles \((s c),\) sable body \((s)\) and vermilion eyes ( \(v\) ), and wild-type males. All females were wild type in the \(\mathrm{F}_{1}\), while all males expressed all three mutant traits. The cross was carried to the \(\mathrm{F}_{2}\) generation and 1000 offspring were counted, with the results shown in the following table. No determination of sex was made in the \(\mathrm{F}_{2}\) data. (a) Using proper nomenclature, determine the genotypes of the \(\mathrm{P}_{1}\) and \(F_{1}\) parents. (b) Determine the sequence of the three genes and the map distance between them. (c) Are there more or fewer double crossovers than expected? (d) Calculate the coefficient of coincidence; does this represent positive or negative interference?

Phenotypically wild \(\mathrm{F}_{1}\) female Drosophila, whose mothers had light eyes (It) and fathers had straw (stw) bristles, produced the following offspring when crossed with homozygous light-straw males:$$\begin{array}{lc} \text { Phenotype } & \text { Number } \\ \hline \text { light-straw } & 22 \\ \text { wild } & 18 \\ \text { light } & 990 \\ \text { straw } & \frac{970}{2000} \end{array}$$ Compute the map distance between the light and straw loci.

Explain why restriction fragment length polymorphisms and microsatellites are important landmarks for mapping purposes.

Colored aleurone in the kernels of corn is due to the dominant allele \(R\). The recessive allele \(r,\) when homozygous, produces colorless aleurone. The plant color (not kernel color) is controlled by another gene with two alleles, \(Y\) and \(y\). The dominant \(Y\) allele results in green color, whereas the homozygous presence of the recessive \(y\) allele causes the plant to appear yellow. In a testross between a plant of unknown genotype and phenotype and a plant that is homozygous recessive for both traits, the following progeny were obtained: colored, green 88 colored, yellow 12 colorless, green 8 colorless, yellow 92 Explain how these results were obtained by determining the exact genotype and phenotype of the unknown plant, including the precise association of the two genes on the homologs (i.e., the arrangement).

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