Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In Drosophila, the two mutations Stubble bristles (Sb) and curled wings ( \(c u\) ) are linked on chromosome III. Sb is a dominant gene that is lethal in a homozygous state, and \(c u\) is a recessive gene. If a female of the genotype \\[ \frac{S b}{+} \\] is to be mated to detect recombinants among her offspring, what male genotype would you choose as her mate?

Short Answer

Expert verified
Answer: The male genotype to best detect recombinants among the offspring when mated with a female genotype of \(Sb/+\) is \(Sb\ sb\ \ cu\ cu\).

Step by step solution

01

Understanding the information given

We are given a female genotype that has Stubble bristles (Sb) and the wild type (+) paired on her chromosome III. The Stubble bristles gene is dominant, but lethal when homozygous. The curly wings gene (\(cu\)) is recessive. The female's genotype is given as: \\[ \frac{Sb}{+} \\]
02

Identifying the possible male genotypes

Since the Sb gene is dominant and lethal in a homozygous state, as well as the \(cu\) gene being recessive, there are 3 possible genotypes for a male that could be the mate: 1. Homozygous recessive for both traits: \(sb\ sb\ \ cu\ cu\) 2. Heterozygous for Stubble bristles and homozygous recessive for curled wings: \(Sb\ sb\ \ cu\ cu\) 3. Homozygous recessive for Stubble bristles and heterozygous for curled wings: \(sb\ sb\ \ Cu\ cu\)
03

Evaluating the potential outcomes

We want a male genotype that, when mated with a female, will help us detect recombinants among the offspring. Let's examine the potential offspring genotypes for each male option: 1. Homozygous recessive for both traits: \(sb\ sb\ \ cu\ cu\) Offspring genotypes would include: *Sb sb Cu cu (wild type with no curly wings) *sb sb Cu cu (recessive phenotype with no Stubble bristles) 2. Heterozygous for Stubble bristles and homozygous recessive for curled wings: \(Sb\ sb\ \ cu\ cu\) Offspring genotypes would include: *Sb sb Cu cu (recessive phenotype) *Sb sb cu cu (recessive phenotype for both traits) 3. Homozygous recessive for Stubble bristles and heterozygous for curled wings: \(sb\ sb\ \ Cu\ cu\) Offspring genotypes would include: *Sb sb Cu Cu (wild type) *Sb sb Cu cu (recessive phenotype for Stubble bristles)
04

Choosing the best male genotype

Considering the possible offspring genotypes from each potential male genotype, the best male genotype to detect recombinants would be the one that results in the most variety of phenotypes in the offspring. In this case, option 2 (Heterozygous for Stubble bristles and homozygous recessive for curled wings: \(Sb\ sb\ \ cu\ cu\)) would give the most variety of phenotypes. Therefore, the male genotype that should be chosen as the mate for the female is \(Sb\ sb\ \ cu\ cu\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linked Genes
In genetics, linked genes refer to genes located close together on the same chromosome, which tend to be inherited together during meiosis. In the case of Drosophila, the genes for Stubble bristles (Sb) and curled wings (\(cu\)) are examples of linked genes because they both reside on chromosome III.
Unlike unlinked genes that assort independently, linked genes do not follow the law of independent assortment. Instead, their close proximity reduces the chances of crossing over between them, meaning they often pass to the next generation as a pair.
Thus, understanding linked genes is vital when predicting offspring's genotypes, especially in exercises that require tracking mutant variations like in Drosophila.
Dominant and Recessive Alleles
Alleles can either be dominant or recessive. Dominant alleles, like the Stubble bristles (Sb), express their traits even if only one copy is present. This means that any organism carrying even one Sb allele will show the characteristic Stubble bristles. However, in a homozygous state, this trait is lethal for Drosophila.
On the other hand, the curly wings gene \(cu\) is recessive. A recessive trait only manifests when an organism has two copies of the recessive allele. Here, this means a Drosophila will only have curly wings if it possesses two copies of the \(cu\) allele.
This dominance-recessive relationship is crucial for understanding how traits like these are passed on to offspring, helping in allele segregation prediction.
Genotype and Phenotype Analysis
The representation of an organism's genetic makeup is known as its genotype, which directly influences the organism's phenotype—the physical expression of traits.
For instance, the female Drosophila described in the exercise has the genotype \(\frac{Sb}{+}\). Her phenotype will be Stubble bristles because the Sb allele is dominant, masking the wild-type (+) phenotype.
Genotype analysis involves examining the combination of alleles an organism has, while phenotype analysis focuses on the visible traits. In genetic exercises, this analysis helps predict the outcome of genetic crosses, revealing the potential appearance of offspring based on certain genotypic pairings.
Recombinant Offspring
Recombinant offspring are a result of genetic recombination, where linked genes are shuffled during meiosis due to crossing over between homologous chromosomes.
This genetic reshuffling creates new allele combinations different from the parent organisms, allowing detectable variations in offspring traits, which is crucial when studying genetic linkage and mapping.
In experiments like the Drosophila genetics problem, choosing the right parental genotypes is essential to successfully observe recombinants. Here, selecting a male genotype like \(Sb\ sb\ \ cu\ cu\) helps maximize variety, facilitating the detection of new combinations of Stubble bristles and curled wings among their offspring.
Lethal Alleles
Lethal alleles are mutations that can result in the death of an organism if present in a certain zygotic combination. In Drosophila, the Sb allele is an example of a dominant lethal allele. If an individual is homozygous for the Sb allele (\(Sb\ Sb\)), it does not survive.
The presence of lethal alleles necessitates careful consideration when predicting offspring viability from genetic crosses. While these alleles can offer interesting insights into genetics, they also serve as natural constraints on the genotypic distributions within populations.
Therefore, geneticists must be mindful of such alleles when analyzing breeding strategies to avoid nonviable progeny.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two different female Drosophila were isolated, each heterozygousfor the autosomally linked genes black body (b), dachs tarsus (d), and curved wings (c). These genes are in the order \(d-b-c\), with \(b\) closer to \(d\) than to \(c .\) Shown in the following table is the genotypic arrangement for each female, along with the various gametes formed by both. Identify which categories are noncrossovers (NCO), single crossovers (SCO), and double crossovers (DCO) in each case. Then, indicate the relative frequency with which each will be produced.

Describe the cytological observation that suggests that crossing over occurs during the first meiotic prophase.

Why is a 50 percent recovery of single-crossover products the upper limit, even when crossing over always occurs between two linked genes?

In Drosophila, Dichaete ( \(D\) ) is a mutation on chromosome III with a dominant effect on wing shape. It is lethal when homozygous. The genes \(e\)bony body \((e)\) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the \(\mathrm{F}_{1}\) progeny with a Dichaete phenotype were backcrossed to the ebony, pink homozygotes. (a) Using the results of this backcross shown in the following table, diagram the cross, showing the genotypes of the parents and offspring of both crosses. (b) What is the sequence and interlocus distance between these three genes?

Why does more crossing over occur between two distantly linked genes than between two genes that are very close together on the same chromosome?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free