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Drosophila females homozygous for the third chromosomal genes pink eye (p) and ebony body (e) were crossed with males homozygous for the second chromosomal gene dumpy wings (dp). Because these genes are recessive, all offspring were wild type (normal). \(F_{1}\) females were testcrossed to triply recessive males. If we assume that the two linked genes ( \(p\) and \(e\) ) are 20 mu apart, predict the results of this cross. If the reciprocal cross were made (F1 males-where no crossing over occurs-with triply recessive females), how would the results vary, if at all?

Short Answer

Expert verified
Answer: The results of testcrosses between F1 dihybrid females and triply recessive males differ from the reciprocal cross involving F1 males with triply recessive females because of the differences in recombination rates and the number of possible phenotypes. The F1 female testcross has 4 possible phenotypes and a 20% chance of recombination, while the reciprocal cross involving F1 males has only 2 possible phenotypes and no crossing over occurs.

Step by step solution

01

Analyze the P generation cross

We are given the following initial cross: - Female: pink eye (p), ebony body (e), homozygous for these genes - Male: dumpy wings (dp), homozygous for this gene Since pink eye, ebony body, and dumpy wings are all recessive, the offspring of this cross will be wild type with normal eyes, body color, and wings. These offspring make up the F1 generation.
02

Determine characteristics of the F1 females

The F1 females will be heterozygous for all three genes: - Pink eye: Pp - Ebony body: Ee - Dumpy wings: Dpdp (since the female will have chromosomes with only normal alleles for the dumpy wing gene) The genotypes of the F1 females will be Pp Ee Dpdp.
03

Perform the F1 female testcross with triply recessive males

Now, the F1 heterozygous females Pp Ee Dpdp are crossed with males that are triply recessive (pp ee dpdp). Due to the 20 mu distance between the linked genes p and e, there will be a 20% chance of recombination between them. Therefore, the expected phenotype percentages of the offspring are as follows: - 40% wild type (normal eye, body, and wings) - P_E_ Dpdp - 20% pink eye, ebony body, dumpy wings (pp ee dpdp) - 20% normal eye, normal body, dumpy wings (P_E_ dpdp) - 20% pink eye, ebony body, normal wings (pp ee Dpdp)
04

Perform the reciprocal cross and predict the results

In the reciprocal cross, F1 males (Pp Ee DpDp) are crossed with triply recessive females (pp ee dpdp). Since no crossing over occurs in male Drosophila, there will be no recombination for the p and e genes. Therefore, the expected phenotype percentages of the offspring are as follows: - 50% normal eye, normal body, dumpy wings (P_E_ dpdp) - 50% pink eye, ebony body, dumpy wings (pp ee dpdp)
05

Compare the results of the two crosses

Comparing the results of the F1 female testcross with the reciprocal cross, we can see that the outcomes do vary: - In the F1 female testcross, there are 4 possible phenotypes and a 20% chance of recombination due to crossing over. - In the reciprocal cross with F1 males, there are only 2 possible phenotypes and no crossing over occurs. Thus, the results do vary between the two crosses because of the differences in recombination rates and the number of possible phenotypes.

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Most popular questions from this chapter

Review the Chapter Concepts list on p. \(121 .\) Most of these center on the process of crossing over between linked genes. Write a short essay that discusses how crossing over can be detected and how the resultant data provide the basis of chromosome mapping.

Why are double-crossover events expected less frequently than single-crossover events?

In Drosophila, a cross was made between females expressing the three X-linked recessive traits, scute bristles \((s c),\) sable body \((s)\) and vermilion eyes ( \(v\) ), and wild-type males. All females were wild type in the \(F_{1},\) while all males expressed all three mutant traits. The cross was carried to the \(\mathrm{F}_{2}\) generation and 1000 offspring were counted, with the results shown in the following table. No determination of sex was made in the \(\mathrm{F}_{2}\) data. (a) Using proper nomenclature, determine the genotypes of the \(P_{1}\) and \(F_{1}\) parents. (b) Determine the sequence of the three genes and the map distance between them. (c) Are there more or fewer double crossovers than expected? (d) Calculate the coefficient of coincidence; does this represent positive or negative interference?

Why is a 50 percent recovery of single-crossover products the upper limit, even when crossing over always occurs between two linked genes?

A female of genotype \\[ \frac{a}{+++} \\] produces 100 meiotic tetrads. Of these, 68 show no crossover events. Of the remaining 32,20 show a crossover between \(a\) and \(b\), 10 show a crossover between \(b\) and \(c,\) and 2 show a double crossover between \(a\) and \(b\) and between \(b\) and \(c .\) Of the 400 gametes produced, how many of each of the eight different genotypes will be produced? Assuming the order \(a-b-c\) and the allele arrangement shown above, what is the map distance between these loci?

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