Question

Indicate the expected number of Barr bodies in interphase cells of individuals with (a) triple \(X\) syndrome \((X X X)\) (b) \(\mathrm{XYY}\) syndrome, (c) Klinefelter syndrome, (d) Turner syndrome, and karyotype \(48, \mathrm{XXXX}\)

Short answer

Answer: Triple X Syndrome - 2 Barr bodies; XYY Syndrome - 0 Barr bodies; Klinefelter Syndrome - 1 Barr body; Turner Syndrome - 0 Barr bodies; Karyotype 48, XXXX - 3 Barr bodies.

Step-by-step solution

Triple X Syndrome (XXX)

For individuals with Triple X Syndrome, they possess three X chromosomes (XXX). Using the formula, we can find the number of Barr bodies: Number of Barr bodies = (Total X chromosomes - 1) = (3 - 1) = 2 Thus, individuals with Triple X Syndrome have 2 Barr bodies in their interphase cells.

XYY Syndrome

For individuals with XYY Syndrome, they possess one X chromosome and two Y chromosomes (XYY). Using the formula, we can find the number of Barr bodies: Number of Barr bodies = (Total X chromosomes - 1) = (1 - 1) = 0 Thus, individuals with XYY Syndrome have 0 Barr bodies in their interphase cells.

Klinefelter Syndrome

For individuals with Klinefelter Syndrome, they possess two X chromosomes and one Y chromosome (XXY). Using the formula, we can find the number of Barr bodies: Number of Barr bodies = (Total X chromosomes - 1) = (2 - 1) = 1 Thus, individuals with Klinefelter Syndrome have 1 Barr body in their interphase cells.

Turner Syndrome

For individuals with Turner Syndrome, they possess one X chromosome only (X). Using the formula, we can find the number of Barr bodies: Number of Barr bodies = (Total X chromosomes - 1) = (1 - 1) = 0 Thus, individuals with Turner Syndrome have 0 Barr bodies in their interphase cells.

Karyotype 48, XXXX

For individuals with karyotype 48, XXXX, they possess four X chromosomes (XXXX). Using the formula, we can find the number of Barr bodies: Number of Barr bodies = (Total X chromosomes - 1) = (4 - 1) = 3 Thus, individuals with karyotype 48, XXXX have 3 Barr bodies in their interphase cells.