Logout Open In App
Open In App
Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Chapter 4: Problem 10

A husband and wife have normal vision, although both of their fathers are red- green color-blind, inherited as an X-linked recessive condition. What is the probability that their first child will be (a) a normal son, (b) a normal daughter, (c) a color-blind son, (d) a color-blind daughter?

Short Answer

Expert verified
Answer: The probabilities for their first child are as follows: - Normal son: 25% - Normal daughter: 25% - Color-blind son: 25% - Color-blind daughter: 25%

Step by step solution

01

1. Identify the genotypes of the parents

The problem states that both the husband and the wife have normal vision, but both of their fathers are red-green color-blind. Since the color-blindness gene is X-linked recessive, we can determine their genotypes: - The husband (the male) has XY chromosomes, and since he is not color-blind, his genotype must be X^NY (N stands for normal, and his Y chromosome does not carry the colorblind gene). - The wife (the female) has XX chromosomes. As both her father and her paternal grandfather were colorblind, she must have inherited an X^N chromosome from her mother, but since she is not colorblind, her genotype must be X^NX^R (R stands for color-blind).
02

2. Create a Punnett square

Now, we will create a Punnett square to determine the genotypes of their potential offspring. With one letter from each parent, the square will look like this: X^N (from father) Y (from father) X^N (from mother) X^NX^N X^NY X^R (from mother) X^NX^R X^RY
03

3. Calculate the probabilities

Using the Punnett square, we can now calculate the probability for each type of child: (a) For a normal son (X^NY): The probability is 1 out of 4 squares, so the probability is 1/4 or 25%. (b) For a normal daughter (X^NX^N): The probability is 1 out of 4 squares, so the probability is 1/4 or 25%. (c) For a color-blind son (X^RY): The probability is 1 out of 4 squares, so the probability is 1/4 or 25%. (d) For a color-blind daughter (X^NX^R): The probability is 1 out of 4 squares, so the probability is 1/4 or 25%. Final probabilities for their first child: - Normal son: 25% - Normal daughter: 25% - Color-blind son: 25% - Color-blind daughter: 25%

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Horses can be cremello (a light cream color), chestnut (a reddish brown color), or palomino (a golden color with white in the horse's tail and mane). Of these phenotypes, only palominos never breed true. The following results have been observed: cremello \(\times\) palomino \(\longrightarrow 1 / 2\) cremello \(1 / 2\) palomino chestnut \(\times\) palomino \(\longrightarrow 1 / 2\) chestnut \(1 / 2\) palomino palomino \(\times\) palomino \(\longrightarrow 1 / 4\) chestnut \(1 / 2\) palomino \(1 / 4\) cremello (a) From these results, determine the mode of inheritance by assigning sene symbols and indicating which genotypes yield which phenotypes. (b) Predict the \(\mathrm{F}_{1}\) and \(\mathrm{F}_{2}\) results of many initial matings between cremello and chestnut horses.

In cattle, coats may be solid white, solid black, or black-and-white spotted. When true-breeding solid whites are mated with truebreeding solid blacks, the \(\mathrm{F}_{1}\) generation consists of all solid white individuals. After many \(\mathrm{F}_{1} \times \mathrm{F}_{1}\) matings, the following ratio was observed in the \(\mathrm{F}_{2}\) generation: \(12 / 16\) solid white \(3 / 16\) black-and-white spotted \(1 / 16\) solid black Explain the mode of inheritance governing coat color by determining how many gene pairs are involved and which genotypes yield which phenotypes. Is it possible to isolate a true-breeding strain of black-and-white spotted cattle? If so, what genotype would they have? If not, explain why not.

While vermilion is X-linked in Drosophila and causes eye color to be bright red, brown is an autosomal recessive mutation that causes the eye to be brown. Flies carrying both mutations lose all pigmentation and are white-eyed. Predict the \(F_{1}\) and \(F_{2}\) results of the following crosses: (a) vermilion females \(\times\) brown males (b) brown females \(\times\) vermilion males (c) white females \(\times\) wild males

Three gene pairs located on separate autosomes determine flower color and shape as well as plant height. The first pair exhibits incomplete dominance, where color can be red, pink (the heterozygote), or white. The second pair leads to the dominant personate or recessive peloric flower shape, while the third gene pair produces either the dominant tall trait or the recessive dwarf trait. Homozygous plants that are red, personate, and tall are crossed with those that are white, peloric, and dwarf. Determine the \(F_{1}\) genotype(s) and phenotype(s). If the \(F_{1}\) plants are inter. bred, what proportion of the offspring will exhibit the same phenotype as the \(\mathrm{P}_{1}\) plants?

With regard to the ABO blood types in humans, determine the genotypes of the male parent and female parent: Male parent: blood type B whose mother was type O Female parent: blood type A whose father was type B Predict the blood types of the offspring that this couple may have and the expected ratio of each.
See all solutions

Recommended explanations on Biology Textbooks

Cellular Energetics

Read Explanation

Microbiology

Read Explanation

Bioenergetics

Read Explanation

Genetic Information

Read Explanation

Communicable Diseases

Read Explanation

Ecosystems

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free