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Albinism in humans is inherited as a simple recessive trait. Determine the genotypes of the parents and offspring for the following families. When two alternative genotypes are possible, list both. (a) Two parents without albinism have five children, four without albinism and one with albinism. (b) A male without albinism and a female with albinism have six children, all without albinism.

Short Answer

Expert verified
Answer: In the first scenario, both parents have a genotype of Aa and their children can have genotypes of AA, Aa, or aa. In the second scenario, the male parent has a genotype of AA and the female parent has a genotype of aa. All their children have a genotype of Aa.

Step by step solution

01

Identify the genotype of the child with albinism

The child with albinism must have the genotype "aa", as it requires two copies of the recessive allele to express the trait.
02

Determine the parents' genotypes from their children

Since the parents have a child with albinism, both parents must carry the recessive allele "a". This means that the parents are both heterozygous (Aa) for the trait, as they both do not express albinism.
03

Determine the genotypes of the other children

These children could have either of the two genotypes without albinism: "AA" or "Aa". To determine the probabilities for each genotype, we can use a Punnett square or calculate probabilities directly. Since both parents are heterozygous (Aa), each child has a 25% chance of being "AA", a 50% chance of being "Aa", and a 25% chance of being "aa" (expressing albinism). In this case, four children without albinism could have either the "AA" or "Aa" genotype. (b) A male without albinism and a female with albinism have six children, all without albinism.
04

Identify the genotype of the female with albinism

Given that the female expresses albinism, her genotype must be "aa".
05

Determine the genotype of the male without albinism from their children

Since all six children are without albinism and have received one allele from each parent, the male without albinism must have the genotype "AA", so his children inherit the "A" allele and do not express albinism.
06

Determine the genotypes of the children

Since the father has the genotype "AA" and the mother has the genotype "aa", each child must inherit one "A" allele from the father and one "a" allele from the mother. Therefore, all six children have the genotype "Aa" without expressing albinism.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recessive Traits
Recessive traits refer to genetic characteristics that are expressed only when an individual has two copies of a recessive allele, represented as "aa." In genetic inheritance, alleles can be either dominant or recessive. Dominant alleles mask the effects of recessive alleles in heterozygous individuals (carriers), whose genotype is "Aa." Such carriers will not express the recessive trait but can pass the recessive allele to their offspring.

Recessive traits typically require genetic analysis to understand their inheritance patterns. This is because a person with a recessive trait must have inherited the recessive allele from both parents. Each parent would thus be a carrier or have the trait themselves.
  • **Example**: Albinism in humans.
  • **Probability**: 25% chance for two heterozygous (Aa) parents to have a child with a recessive trait (aa).
This means understanding recessive traits is crucial for predicting the likelihood of certain genetic traits appearing in offspring.
Genotype
The term "genotype" describes the genetic makeup of an individual with respect to a particular trait. It refers to the specific alleles that an organism carries in its cells. Unlike the phenotype, which is the physical expression of a trait, the genotype provides the genetic blueprint.

Genotypes are denoted by letters, with a common convention being:
  • **'AA'** - Homozygous dominant
  • **'Aa'** - Heterozygous
  • **'aa'** - Homozygous recessive
This notation helps in predicting inheritance patterns, as seen in the study of genetic traits like albinism. By analyzing parents' genotypes, one can predict possible offspring characteristics using tools like the Punnett square. Genotype analysis is vital in genetic counseling to assess and address potential hereditary conditions.
Albinism
Albinism is a condition caused by a lack of melanin pigment in the skin, hair, and eyes. It is inherited as a recessive trait, which means an individual must inherit two recessive alleles ("aa") to express it physically. People with albinism often have lighter skin and hair, along with vision problems, due to the lack of pigmentation.

The disorder results from a mutation that affects melanin production, vital for coloration in skin, hair, and eyes. Since parents without albinism can still have children with albinism if both carry the recessive allele (Aa), understanding albinism requires comprehending recessive inheritance patterns. With both parents carrying one recessive allele, there is a 25% chance with each pregnancy that the child will have albinism if the alleles combine as "aa."
  • Prevention: Genetic screenings can help identify carriers.
  • Management: Sun protection and vision support are vital for affected individuals.
By studying albinism, researchers can uncover insights into genetic mutations and inheritance.
Punnett Square
The Punnett square is a simple graphical tool used to predict the possible genotypes of offspring from parental genetic combinations. It helps determine the probability of an offspring inheriting particular alleles. To create a Punnett square, you list one parent's alleles on the top and the other parent's alleles on the side, then fill in the squares inside.

In genetic problems, the Punnett square is particularly useful for visualizing how traits like albinism are inherited, especially when considering heterozygous parents ("Aa"). For example:
  • Top Row: Possibly "A" or "a" alleles from one parent
  • Side Column: Possibly "A" or "a" alleles from the other parent
The resulting boxes reflect all potential allele combinations for the offspring. This visualization illustrates not only the probability of different genotypes but also enhances understanding of genetic inheritance. Such tools are essential for those studying genetics to quickly and easily calculate genetic outcomes.

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Most popular questions from this chapter

In Drosophila, gray body color is dominant over ebony body color, while long wings are dominant over vestigial wings. Work the following crosses through the \(F_{2}\) generation, and determine the genotypic and phenotypic ratios for each generation. Assume that the \(P_{1}\) individuals are homozygous: (a) gray, long \(\times\) ebony, vestigial, and (b) gray, vestigial \(\times\) ebony, long, and (c) gray, long \(\times\) gray, vestigial.

Consider three independently assorting gene pairs, \(A / a, B / b,\) and \(C / c,\) where each demonstrates typical dominance \((A-, B-, C-)\) and recessiveness \((a a, b b, c c) .\) What is the probability of obtain ing an offspring that is \(A A B b C c\) from parents that are \(A a B b C C\) and \(A A B b C c ?\)

Why was the garden pea a good choice as an experimental organism in Mendel's work?

Correlate Mendel's four postulates with what is now known about homologous chromosomes, genes, alleles, and the process of meiosis.

When working out genetics problems in this and succeeding chapters, always assume that members of the \(P_{1}\) generation are homozygous, unless the information or data you are given require you to do otherwise In this chapter, we focused on the Mendelian postulates, probability, and pedigree analysis. We also considered some of the methods and reasoning by which these ideas, concepts, and techniques were developed. On the basis of these discussions, what answers would you propose to the following questions: (a) How was Mendel able to derive postulates concerning the behavior of "unit factors" during gamete formation, when he could not directly observe them? (b) How do we know whether an organism expressing a dominant trait is homozygous or heterozygous? (c) In analyzing genetic data, how do we know whether deviation from the expected ratio is due to chance rather than to another, independent factor? (d) since experimental crosses are not performed in humans, how do we know how traits are inherited?

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