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ConsiderapopulationinwhichthefrequencyofalleleAisp \(=0.7\) and thefrequencyofalleleais \(q=0.3\), andwheretheallelesarecodominant. What will be the allele frequencies after one generation if the following occurs? (a) \(w_{A A}=1, w_{A a}=0.9, w_{a a}=0.8\) (b) \(w_{A A}=1, w_{A a}=0.95, w_{a a}=0.9\) (c) \(w_{A A}=1, w_{A a}=0.99, w_{a a}=0.98\) (d) \(w_{A A}=0.8, w_{A a}=1, w_{a a}=0.8\)

Short Answer

Expert verified
Question: Calculate the new allele frequencies after one generation for each given case. Answer: (a) p ≈ 0.692, q ≈ 0.308 (b) p ≈ 0.695, q ≈ 0.305 (c) p ≈ 0.698, q ≈ 0.302 (d) p ≈ 0.702, q ≈ 0.298

Step by step solution

01

Calculate the initial genotype frequencies

Using the given initial allele frequencies (\(p = 0.7\), \(q = 0.3\)), we can calculate the initial genotype frequencies: \(AA: p^2 = (0.7)^2 = 0.49\) \(Aa: 2pq = 2(0.7)(0.3) = 0.42\) \(aa: q^2 = (0.3)^2 = 0.09\)
02

Calculate the resultant genotype frequencies after selection

Now apply the selection coefficients given in each part of the problem to calculate the resultant genotype frequencies after selection: (a) \(AA: 1 \times 0.49 = 0.49\) \(Aa: 0.9 \times 0.42 = 0.378\) \(aa: 0.8 \times 0.09 = 0.072\) (b) \(AA: 1 \times 0.49 = 0.49\) \(Aa: 0.95 \times 0.42 = 0.399\) \(aa: 0.9 \times 0.09 = 0.081\) (c) \(AA: 1 \times 0.49 = 0.49\) \(Aa: 0.99 \times 0.42 = 0.4158\) \(aa: 0.98 \times 0.09 = 0.0882\) (d) \(AA: 0.8 \times 0.49 = 0.392\) \(Aa: 1 \times 0.42 = 0.42\) \(aa: 0.8 \times 0.09 = 0.072\)
03

Calculate the new allele frequencies after selection

To determine the new allele frequencies, normalize the genotype frequencies and then apply the Hardy-Weinberg equilibrium formulas: (a) Total frequency after selection: \(0.49 + 0.378 + 0.072 = 0.94\) New allele frequencies: \(p = \frac{0.49 + 0.5 \times 0.378}{0.94} \approx 0.692\), \(q = \frac{0.072 + 0.5 \times 0.378}{0.94} \approx 0.308\) (b) Total frequency after selection: \(0.49 + 0.399 + 0.081 = 0.97\) New allele frequencies: \(p = \frac{0.49 + 0.5 \times 0.399}{0.97} \approx 0.695\), \(q = \frac{0.081 + 0.5 \times 0.399}{0.97} \approx 0.305\) (c) Total frequency after selection: \(0.49 + 0.4158 + 0.0882 = 0.994\) New allele frequencies: \(p = \frac{0.49 + 0.5 \times 0.4158}{0.994} \approx 0.698\), \(q = \frac{0.0882 + 0.5 \times 0.4158}{0.994} \approx 0.302\) (d) Total frequency after selection: \(0.392 + 0.42 + 0.072 = 0.884\) New allele frequencies: \(p = \frac{0.392 + 0.5 \times 0.42}{0.884} \approx 0.702\), \(q = \frac{0.072 + 0.5 \times 0.42}{0.884} \approx 0.298\) Hence, we have found the new allele frequencies after one generation for each given case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Codominant Alleles
In genetics, when alleles are codominant, both alleles in a heterozygous individual contribute to the phenotype. This means that each parent passes on an allele that equally affects the offspring's traits. Unlike complete dominance, where one allele masks the effect of another, codominance allows both alleles to be fully and independently expressed.
For example, if you imagine a flower color determined by two codominant alleles, a flower with the genotype Aa may show both color traits represented by A and a.
This concept is crucial in the exercise, as it assumes codominant alleles for computations of allele and genotype frequencies across generations. Codominance leads to observable differences in offspring and plays a key role in understanding how traits are passed on when no allele overpowers another.
Genotype Frequencies
Genotype frequencies are essential in predicting the genetic makeup of a population. They reflect how common specific genetic combinations (AA, Aa, aa) are within a population. To calculate these frequencies, we typically utilize the Hardy-Weinberg principle. With the initial allele frequencies provided (p = 0.7, q = 0.3), the genotypes are computed as follows:
  • AA: \( p^2 = (0.7)^2 = 0.49 \)
  • Aa: \( 2pq = 2(0.7)(0.3) = 0.42 \)
  • aa: \( q^2 = (0.3)^2 = 0.09 \)
The genotype frequencies help us understand how alleles are paired within the population and predict the traits seen in the next generation. They change based on selection pressure and other evolutionary forces, a concept further explored in our selection coefficients section.
Selection Coefficients
Selection coefficients measure the relative fitness of different genotypes within a population. Each coefficient indicates how likely a genotype is to survive and reproduce compared to others. In the given exercise, they influence the resulting genotype frequencies after one generation.
For example, in scenario (a), the selection coefficients are \( w_{A A}=1 \), \( w_{A a}=0.9 \), and \( w_{a a}=0.8 \). These coefficients imply that individuals with genotype AA are more likely to pass on their genes than those with genotype aa. The effect of these coefficients will modify the genotype frequencies:
  • AA stays at 0.49 (unchanged because its coefficient is 1)
  • Aa reduces to 0.378 because \( 0.9 imes 0.42 = 0.378 \)
  • aa drops to 0.072 because \( 0.8 imes 0.09 = 0.072 \)
Selection coefficients play a pivotal role in evolutionary biology by determining how populations adapt over time.
Hardy-Weinberg Equilibrium
The Hardy-Weinberg equilibrium is a fundamental principle in population genetics. It proposes that allele and genotype frequencies within a large, randomly-mating population remain constant unless disturbed by evolutionary forces. This equilibrium provides a mathematical baseline to detect the impact of forces like selection, mutation, migration, and genetic drift.
To check if a population is in Hardy-Weinberg equilibrium, you need to compare observed and expected genotype frequencies calculated from allele frequencies. For example, if a population's observed genotype frequencies match those predicted by \( p^2 + 2pq + q^2 = 1 \), it suggests that the population is not undergoing forces that alter its genetic structure.
Even though the exercise above assumes codominance and selection, the Hardy-Weinberg model helps establish initial conditions before the application of selection coefficients. This principle is useful as a starting point for understanding how populations evolve over time when subject to various pressures.

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Most popular questions from this chapter

Recent reconstructions of evolutionary history are often dependent on assigning divergence in terms of changes in amino acid or nucleotide sequences. For example, a comparison of cytochrome c shows 10 amino acid differences between humans and dogs, 24 differences between humans and moths, and 38 differences between humans and yeast. Such data provide no information as to the absolute times of divergence for humans, dogs, moths, and yeast. How might one calibrate the molecular clock to an absolute time clock? What problems might one encounter in such a calibration?

CONCEPT QUESTION Read the Chapter Concepts liston page 412 All these pertain to the principles of population genetics and the evolution of species. Write a short essay describing the roles of mutation, migration, and selection in bringing about speciation.

The original source of new alleles, upon which selection operates, is mutation, a random event that occurs without regard to selectional value in the organism. Although many model organisms have been used to study mutational events in populations, some investigators have developed abiotic molecular models. Soll et al. (2006. Genetics 175:267-275) examined one such model to study the relationship between both deleterious and advantageous mutations and population size in a ligase molecule composed of RNA (a ribozyme). Soll found that the smaller the population of molecules, the more likely it was that not only deleterious mutations but also advantageous mutations would disappear. Why would population size influence the survival of both types of mutations (deleterious and advantageous) in populations?

What are considered significant factors in maintaining the surprisingly high levels of genetic variation in natural populations?

List the barriers that prevent interbreeding, and give an example of each.

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