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Two plants in a cross were each heterozygous for two gene pairs \((A b / a B)\) whose loci are linked and 25 mu apart. Assuming that crossing over occurs during the formation of both male and female gametes and that the \(A\) and \(B\) alleles are dominant, determine the phenotypic ratio of their offspring.

Short Answer

Expert verified
The phenotypic ratio of the offspring produced by these two heterozygous plants is 19:5, with 19 representing the dominant (A and B) phenotype and 5 representing the recessive (a and b) phenotype.

Step by step solution

01

Determine all possible gamete combinations

For plants that are heterozygous for both gene pairs (A b / a B), there are four possible gametes formed from the alleles (Aa and Bb) in each plant. These gametes are AB, Ab, aB, and ab.
02

Calculate the recombination frequency (RF)

The recombination frequency (RF) between two gene pairs is given by the distance between them in map units (mu). In this exercise, the two gene pairs are 25 mu apart. So, the recombination frequency (RF) is 25%. This means that 25% of the offspring will have recombinant gametes, while 75% will have the original non-recombinant gametes.
03

Determine the proportions of each gamete type

Knowing the recombination frequency (RF), we can now determine the proportions of gametes that are parental and recombinant. For the non-recombinant (parental) gametes, it will be 75% (100% - RF). Hence, 75% of the gametes will be parental (AB and ab or Ab and aB). For the recombinant gametes, it will be 25% of the gametes (Ab and aB or AB and ab).
04

Calculate the offspring's phenotype using the Punnett square

Next, we will use the Punnett square to determine the phenotypic ratio of the offspring by combining the gametes from both parents. | | AB | Ab | aB | ab | |---------|------------|------------|------------|------------| | AB | AABB | AABb | AaBB | AaBb | | Ab | AABb | AAbb | AaBb | Aabb | | aB | AaBB | AaBb | aaBB | aaBb | | ab | AaBb | Aabb | aaBb | aabb |
05

Calculate the phenotypic ratio

Based on the Punnett square, the resulting offspring phenotypes are: - AABB: 1/16 - AABb: 4/16 - AaBB: 4/16 - AaBb: 10/16 - AAbb: 2/16 - Aabb: 4/16 - aaBB: 2/16 - aaBb: 4/16 - aabb: 1/16 The dominant phenotypes (expressing the A and B alleles) are AABB, AABb, AaBB, and AaBb, which account for a total of (1 + 4 + 4 + 10)/16 = 19/16 of the offspring. Since both A and B are dominant, the phenotypic ratio of the offspring would be expressed as: Dominant (A and B): 19/16 Recessive (a and b): 5/16 In conclusion, the phenotypic ratio of the offspring produced by two heterozygous plants for two gene pairs (A b / a B) that are 25 mu apart is 19:5 for the dominant (A and B) phenotype to the recessive (a and b) phenotype.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Genetic Linkage
Genetic linkage refers to the phenomenon where genes that are located close to each other on the same chromosome tend to be inherited together during meiosis. This is because the chance of a crossover event occurring between closely linked genes is low, which means that the alleles for these genes are usually passed down to offspring in the same combinations as those found in the parents. The closer the genes are on the chromosome, the lower the probability of recombination between them. In our exercise, the two heterozygous gene pairs (A b / a B) are said to be linked, which affects the variety of possible genetic combinations in the offspring.
Recombination Frequency
Recombination frequency is a measure of the likelihood of a crossover event between two genetic loci and is used to estimate the genetic distance between them. It is typically expressed as a percentage or as map units (mu). The higher the recombination frequency, the further apart the genes are on a chromosome. In our exercise, a recombination frequency of 25% means that a quarter of the offspring will display gene combinations different from those of the parents, indicative of a crossover event. The given 25 mu distance suggests a relatively high chance for recombination to occur.
Punnett Square
A Punnett square is a grid used to predict the genotypic and phenotypic outcomes of a cross between two organisms. Each square represents a possible genotype of the offspring, derived from the combination of alleles that each parent can provide. By filling out a Punnett square, as demonstrated in the exercise, you can visualize the genetic makeup of future generations and determine the expected ratios of different phenotypes.
Phenotypic Ratio
The phenotypic ratio is the relative number of offspring with different traits that result from a genetic cross. This ratio is derived from interpreting the genotypes produced by a Punnett square in terms of observable characteristics, taking into account the dominance and recessiveness of alleles. The exercise provided us with a phenotypic ratio that takes into account the dominant (expressing A and B alleles) and recessive (expressing a and b alleles) phenotypes.
Map Units
Map units, or centimorgans (cM), are a unit of measurement for genetic distance used in genetic linkage maps. One map unit represents a 1% chance that a crossover will occur between two genes during meiosis. This value is crucial in genetic mapping as it helps to estimate the physical distance between genes on a chromosome. In the context of our exercise, the 25 map units between the linked genes indicate a moderate distance, suggesting a reasonable expectation of crossover events.
Heterozygous Gene Pairs
Heterozygous gene pairs occur when an organism has two different alleles at a particular genetic locus. In the exercise, the plants were heterozygous for two gene pairs (A b / a B), meaning that for each gene locus, there is one dominant and one recessive allele. This heterozygosity results in varied gamete combinations and is fundamental to the diversity observed in offspring's genotypes and phenotypes.
Dominant and Recessive Alleles
Alleles can be dominant or recessive, affecting the outcome of a trait in an organism. A dominant allele will mask the expression of a recessive allele in a heterozygote. Thus, only one dominant allele is required to express a dominant trait. Conversely, a recessive trait requires two copies of the recessive allele to be expressed. In the exercise, the A and B alleles were dominant, and thus the phenotypes they influenced were more prevalent in the offspring, as opposed to the recessive a and b alleles.

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Most popular questions from this chapter

Traditional gene mapping has been applied successfully to a variety of organisms including yeast, fungi, maize, and Drosophila. However, human gene mapping has only recently shared a similar spotlight. What factors have delayed the application of traditional gene-mapping techniques in humans?

A female of genotype \\[ \frac{a}{+}+\frac{b}{+}+ \\] produces 100 meiotic tetrads. Of these, 68 show no crossover events. Of the remaining 32,20 show a crossover between \(a\) and \(b\) 10 show a crossover between \(b\) and \(c,\) and 2 show a double crossover between \(a\) and \(b\) and between \(b\) and \(c .\) Of the 400 gametes produced, how many of each of the 8 different genotypes will be produced? Assuming the order \(a-b-c\) and the allele arrangement previously shown, what is the map distance between these loci?

Are mitotic recombinations and sister chromatid exchanges effective in producing genetic variability in an individual? in the offspring of individuals?

In this chapter, we focused on linkage, chromosomal mapping, and many associated phenomena. In the process, we found many opportunities to consider the methods and reasoning by which much of this information was acquired. From the explanations given in the chapter, what answers would you propose to the following fundamental questions? (a) How was it established experimentally that the frequency of recombination (crossing over) between two genes is related to the distance between them along the chromosome? (b) How do we know that specific genes are linked on a single chromosome, in contrast to being located on separate chromosomes? (c) How do we know that crossing over results from a physical exchange between chromatids? (d) How do we know that sister chromatids undergo recombination during mitosis? (e) When designed matings cannot be conducted in an organism (for example, in humans), how do we learn that genes are linked, and how do we map them?

In Drosophila, a cross was made between females-all expressing the three X-linked recessive traits scute bristles (sc), sable body (s), and vermilion eyes (v)-and wild-type males. In the \(\mathrm{F}_{1}\), all females were wild type, while all males expressed all three mutant traits. The cross was carried to the \(\mathrm{F}_{2}\) generation, and 1000 offspring were counted, with the results shown in the following table. $$\begin{array}{ll} \text { Phenotype } & \text { Offspring } \\ \text { se } s \quad v & 314 \\ +++ & 280 \\ +s v & 150 \\ s c++ & 156 \\ s c+v & 46 \\ +s+ & 30 \\ s c s+ & 10 \\ ++v & 14 \end{array}$$ No determination of sex was made in the data. (a) Using proper nomenclature, determine the genotypes of the \(P_{1}\) and \(F_{1}\) parents. (b) Determine the sequence of the three genes and the map distances between them. (c) Are there more or fewer double crossovers than expected? (d) Calculate the coefficient of coincidence. Does it represent positive or negative interference?

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