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A husband and wife have normal vision, although both of their fathers are red- green color-blind, an inherited X-linked recessive condition. What is the probability that their first child will be (a) a normal son, (b) a normal daughter, (c) a color-blind son, (d) a color-blind daughter?

Short Answer

Expert verified
Answer: The probabilities for each specific characteristic are as follows: (a) 25% chance of having a normal son, (b) 25% chance of having a normal daughter, (c) 25% chance of having a color-blind son, (d) 0% chance of having a color-blind daughter.

Step by step solution

01

Determine the genotypes of the parents

Since red-green color blindness is X-linked, we will label the normal X chromosome as XN and the color-blind X chromosome as Xc. The father has normal vision, so he must have one normal X chromosome (XN) from his mother and a Y chromosome. The mother also has normal vision, but her father is color-blind, so she must have one normal X chromosome (XN) and one color-blind X chromosome (Xc). Thus, the genotypes are Father: XN Y and Mother: XN Xc.
02

Create a Punnett square

Set up a Punnett square to find the combinations of X and Y chromosomes that can result from the parents' genotypes: | XN Mother | Xc Mother -------|-----------|---------- XN Dad | XN XN | XN Xc Y Dad| XN Y | Xc Y
03

Identify and calculate probabilities for each child's characteristics

Now, using the Punnett square, we will identify the probabilities of each child's characteristics: (a) Normal son: XN Y - This combination is present in 1 of the 4 cells, so the probability is 1/4 or 25%. (b) Normal daughter: XN XN - This combination is present in 1 of the 4 cells, so the probability is 1/4 or 25%. (c) Color-blind son: Xc Y - This combination is present in 1 of the 4 cells, so the probability is 1/4 or 25%. (d) Color-blind daughter: There is no Xc Xc combination in the Punnett square, thus the probability is 0/4 or 0%. In conclusion, the probabilities for the couple's first child are: (a) 25% chance of having a normal son, (b) 25% chance of having a normal daughter, (c) 25% chance of having a color-blind son, (d) 0% chance of having a color-blind daughter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Punnett Square
The Punnett square is a simple illustrative tool used in genetics to predict the possible genotypes of offspring from a particular cross. It's a grid that allows us to combine the genetic contributions of each parent in a visual format. For X-linked recessive conditions like red-green color blindness, where the gene is located on the X chromosome, the Punnett square helps us understand how the condition is inherited.

Parents' chromosomes are placed on the top and side of the square, and the potential combinations they can produce are shown in the grids. Since males possess one X and one Y chromosome (XY), and females have two X chromosomes (XX), the Punnett square accounts for each possible combination ensuring a clear, visual representation of genetic transmission.
Genotype
Genotype refers to the specific genetic makeup of an individual, in other words, the set of genes that the individual carries. For X-linked traits, the genotype typically involves the alleles on the X chromosome. In the case of red-green color blindness, which is a recessive condition, the genotype will manifest as the condition only if two recessive alleles are present in females (XX) or one in males (XY) because males lack a second X chromosome.

Understanding the parental genotypes is crucial in genetics problems as it helps us predict the possible genotypes (and therefore phenotypes) of their offspring. The father's genotype is XY and the mother's is XX, but since she is a carrier for color blindness, it is denoted as XN (normal) Xc (carrying color-blind allele).
Red-Green Color Blindness
Red-green color blindness is an X-linked recessive condition meaning it's carried on the X chromosome and a male would only need one affected copy of the gene to express the condition since they have only one X chromosome (XY). Females, having two X chromosomes (XX), would need two affected copies of the gene to exhibit red-green color blindness.

Due to this mode of inheritance, it is much more common in males than females. Being recessive, a female can be a carrier of the condition without expressing it, which is pivotal in understanding the inheritance pattern. A carrier female can pass on the trait to her offspring, potentially affecting her male progeny with higher probability.
Probability in Genetics
Probability in genetics refers to the likelihood of a particular genetic outcome occurring. It is grounded in the Law of Segregation and Independent Assortment, which are fundamental principles of inheritance. The Punnett square informs us about the probability of each genotype arising from a cross.

For example, by calculating the frequencies of particular genotypes or phenotypes appearing in the Punnett square grid, we can articulate the probability of an offspring with either characteristic. In the case of red-green color blindness, probability helps quantify the chances of children inheriting the condition from carrier parents.

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Most popular questions from this chapter

In a plant, a tall variety was crossed with a dwarf variety. All \(\mathrm{F}_{1}\) plants were tall. When \(\mathrm{F}_{1} \times \mathrm{F}_{1}\) plants were interbred, \(9 / 16\) of the \(\mathrm{F}_{2}\) were tall and \(7 / 16\) were dwarf. (a) Explain the inheritance of height by indicating the number of gene pairs involved and by designating which genotypes yield tall and which yield dwarf. (Use dashes where appropriate.) (b) What proportion of the \(F_{2}\) plants will be true breeding if self- fertilized? List these genotypes.

In Shorthorn cattle, coat color may be red, white, or roan. Roan is an intermediate phenotype expressed as a mixture of red and white hairs. The following data are obtained from various crosses: red \(\times\) red \(\longrightarrow\) all red white \(\times\) white \(\longrightarrow\) all white red \(\times\) white \(\longrightarrow\) all roan \\[\text { roan } \times \operatorname{roan} \longrightarrow 1 / 4 \text { red: } 1 / 2\\] roan: \(1 / 4\) white (a) How is coat color inherited? What are the genotypes of parents and offspring for each cross? (b) Does the roan phenotype illustrate a case of incomplete dominance or a case of codominance? Explain.

In mice, a short-tailed mutant was discovered. When it was crossed to a normal long-tailed mouse, 4 offspring were short-tailed and 3 were long-tailed. Two short-tailed mice from the \(\mathrm{F}_{1}\) generation were selected and crossed. They produced 6 short-tailed and 3 long-tailed mice. These genetic experiments were repeated three times with approximately the same results. What genetic ratios are illustrated? Hypothesize the mode of inheritance and diagram the crosses.

In four o'clock plants, many flower colors are observed. In a cross involving two true-breeding strains, one crimson and the other white, all of the \(\mathrm{F}_{1}\) generation were rose color. In the \(\mathrm{F}_{2}\), four new phenotypes appeared along with the \(P_{1}\) and \(F_{1}\) parental colors. The following ratio was obtained: Propose an explanation for the inheritance of these flower colors.

In chickens, a condition referred to as "creeper" exists whereby the bird has very short legs and wings and appears to be creeping when it walks. If creepers are bred to normal chickens, one-half of the offspring are normal and one-half are creepers. Creepers never breed true. If bred together, they yield two-thirds creepers and one-third normal. Propose an explanation for the inheritance of this condition.

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