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In humans, the \(A B O\) blood type is under the control of autosomal multiple alleles. Color blindness is a recessive X-linked trait. If two parents who are both type \(A\) and have normal vision produce a son who is color-blind and is type \(\mathrm{O},\) what is the probability that their next child will be a female who has normal vision and is type \(\mathrm{O} ?\)

Short Answer

Expert verified
Answer: The probability is 1 in 8, or 12.5%.

Step by step solution

01

Determine the Parents' Genotypes

Since both parents have type A blood, they could have genotypes AA, AO. We know their son has type O blood, so they both must carry the O allele; thus, their genotypes are AO. Both parents have normal vision, so the mother's genotype is X^N X^N or X^N X^n and the father's genotype is X^NY.
02

Set up Punnett Square for Blood Type

Cross the parents' genotypes for blood type (AO x AO) in a Punnett square to find the possible blood types of their offspring. ``` A | O -------- A |AA | AO O |OA | OO ``` In this Punnett square, the probability that a child will have type O blood is 1 in 4 (OO).
03

Set up Punnett Square for Vision

Cross the parents' genotypes for vision (mother: X^N X^n, father: X^NY) in a Punnett square to find the possible genotypes of their offspring related to vision. ``` X^N | X^n --------- X^N |X^N X^N| X^N X^n Y | X^NY | X^nY ``` In this Punnett square, the probability that a child will be female with normal vision is 1 in 2 (X^N X^N).
04

Calculate the Probability of the Desired Combination

To find the probability that their next child will be a female with normal vision and type O blood, multiply the probabilities found in Steps 2 and 3: (1/4) x (1/2) = 1/8. The probability that their next child will be a female with normal vision and type O blood is 1 in 8, or 12.5%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Punnett Square
The Punnett square is a visual tool in genetics used to predict the possible genotypes of offspring based on the genotypes of their parents. It is named after Reginald Punnett, who devised the approach to demonstrate how alleles can segregate and recombine during sexual reproduction. The square is drawn as a grid, with one parent's alleles listed along the top and the other parent's along the side. Each square within the grid represents a possible genotype for an offspring.

For example, with blood types, the alleles can be A, B, or O. If two parents both have type A blood, but their genotypes are AO (since they can pass on an O), the Punnett square will show the four possible combinations for their children: AA, AO, OA, and OO. This grid effectively illustrates why there is a 1 in 4 chance of any child they have possessing type O blood. The simplicity and visual nature of the Punnett square make it invaluable in understanding genetics basics.
Autosomal Multiple Alleles
Unlike most traits, which are determined by a simple pair of alleles, some traits have more than two alleles governing them. This is known as multiple allele inheritance and is where genes on autosomal chromosomes (non-sex chromosomes) exhibit more than two forms. The human ABO blood group system is an excellent example of this concept, with three alleles involved: A, B, and O.

However, each person still inherits only two alleles (one from each parent), and the O allele is recessive to both A and B. Therefore, a child's blood type depends on the combination of alleles received from their parents. Because of multiple alleles, genetic outcomes can be more varied and complex. The step-by-step solution of the exercise utilizes this principle to deduce the parents' genotypes as AO, given that they have a type O offspring, indicating they both carry the recessive O allele.
X-linked Recessive Traits
Some genetic traits are linked to the X chromosome and exhibit a pattern of inheritance different from traits carried on autosomal chromosomes. X-linked traits are often recessive, meaning that the trait will only be expressed in females if they inherit two copies of the recessive allele (one from each parent). In males, who have only one X chromosome, the presence of a single recessive allele is sufficient for the trait to appear since there is no second allele to potentially mask its effects.

Color blindness is an example of an X-linked recessive trait. The exercise solution illustrates how to determine the probability of having a daughter with normal vision, which requires she inherit at least one X chromosome with the normal vision allele (denoted as X^N). The Punnett square shows that there's a 50% chance of a female offspring receiving two X^N alleles, given the potential for an X^n carrier mother. These concepts, paired with an understanding of Punnett squares, help dissect the genetic outcomes in such scenarios.

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Most popular questions from this chapter

In foxes, two alleles of a single gene, \(P\) and \(p,\) may result in lethality \((P P),\) platinum coat \((P p),\) or silver coat \((p p) .\) What ratio is obtained when platinum foxes are interbred? Is the \(P\) allele behaving dominantly or recessively in causing (a) lethality; (b) platinum coat color?

In rabbits, a series of multiple alleles controls coat color in the following way: \(C\) is dominant to all other alleles and causes full color. The chinchilla phenotype is due to the \(c^{\mathrm{ch}}\) allele, which is dominant to all alleles other than \(C\). The \(c^{h}\) allele, dominant only to \(c^{a}\) (albino), results in the Himalayan coat color. Thus, the order of dominance is \(C>c^{\mathrm{dh}}>c^{h}>c^{a} .\) For each of the fol- lowing three cases, the phenotypes of the \(\mathrm{P}_{1}\) generations of two crosses are shown, as well as the phenotype of one member of the \(\mathrm{F}_{1}\) generation. For each case, determine the genotypes of the \(P_{1}\) generation and the \(\mathrm{F}_{1}\) offspring, and predict the results of making each indicated cross between \(F_{1}\) individuals.

Proto-oncogenes stimulate cells to progress through the cell cycle and begin mitosis. In cells that stop dividing, transcription of proto-oncogenes is inhibited by regulatory molecules. As is typical of all genes, proto-oncogenes contain a regulatory DNA region followed by a coding DNA region that specifies the amino acid sequence of the gene product. Consider two types of mutation in a proto-oncogene, one in the regulatory region that eliminates transcriptional control and the other in the coding region that renders the gene product inactive. Characterize both of these mutant alleles as either gain-of-function or loss-of-function mutations and indicate whether each would be dominant or recessive.

In goats, the development of the beard is due to a recessive gene. The following cross involving true-breeding goats was made and carried to the \(\mathrm{F}_{2}\) generation: Offer an explanation for the inheritance and expression of this trait, diagramming the cross. Propose one or more crosses to test your hypothesis.

Horses can be cremello (a light cream color), chestnut brownish color), or palomino (a golden color with white in the horse's tail and mane). Of these phenotypes, only palominos never breed true. (a) From the results given above, determine the mode of inheritance by assigning gene symbols and indicating which genotypes yield which phenotypes. (b) Predict the \(F_{1}\) and \(F_{2}\) results of many initial matings between cremello and chestnut horses.

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