Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Mendel crossed peas having round seeds and yellow cotyledons (seed leaves) with peas having wrinkled seeds and green cotyledons. All the \(F_{1}\) plants had round seeds with yellow cotyledons. Diagram this cross through the \(\mathrm{F}_{2}\) generation, using both the Punnett square and forked-line, or branch diagram, methods.

Short Answer

Expert verified
In Mendel's pea experiment, given the traits for seed shape (round or wrinkled) and cotyledon color (yellow or green), we determined the F2 generation genotypes using both Punnett square and forked-line methods. The F2 generation genotypes are distributed as follows: 1 RRYY (round seeds, yellow cotyledons), 2 RrYY (round seeds, yellow cotyledons), 1 rrYY (wrinkled seeds, yellow cotyledons), 2 RRYy (round seeds, green cotyledons), 4 RrYy (round seeds, green cotyledons), 2 rrYy (wrinkled seeds, green cotyledons), 1 RRyy (round seeds, green cotyledons), 2 Rryy (round seeds, green cotyledons), and 1 rryy (wrinkled seeds, green cotyledons).

Step by step solution

01

Determine the F1 generation genotypes

Using the Punnett square method, we will find the possible genotype combinations for the F1 generation. Since both traits are inherited independently, we only need to cross the genotypes for each trait separately and then combine the results. Seed shape (R and r) cross: ``` R R r Rr Rr r Rr Rr ``` Cotyledon color (Y and y) cross: ``` Y Y y Yy Yy y Yy Yy ``` Combine the two results: all F1 generation plants have the genotype RrYy (round seeds, yellow cotyledons).
02

Set up the F2 generation genotypes

For the F2 generation, we will need to cross the F1 generation plants (RrYy) with themselves. Again, we will first cross the genotypes for seed shape and cotyledon color separately and then combine the results.
03

Determine the F2 generation seed shape genotypes using the Punnett square method

Cross the Rr genotype for seed shape (for F1 plants) with itself: ``` R r R RR Rr r Rr rr ``` We have the genotypes: RR (1), Rr (2), and rr (1) for the F2 generation seed shape.
04

Determine the F2 generation cotyledon color genotypes using the Punnett square method

Cross the Yy genotype for cotyledon color (for F1 plants) with itself: ``` Y y Y YY Yy y Yy yy ``` We have the genotypes: YY (1), Yy (2), and yy (1) for the F2 generation cotyledon color.
05

Combine the F2 generation results using the forked-line method

Now we can combine the results from steps 3 and 4 using the forked-line method. * Seed shape: 1 (RR) : 2 (Rr) : 1 (rr) * Cotyledon color: 1 (YY) : 2 (Yy) : 1 (yy) Using forked-line method: ``` 1 (RRYY) : 2 (RrYY) : 1 (rrYY) // seed shape combined with YY 2 (RRYy) : 4 (RrYy) : 2 (rrYy) // seed shape combined with Yy 1 (RRyy) : 2 (Rryy) : 1 (rryy) // seed shape combined with yy ``` The F2 generation genotypes are distributed as follows: 1 RRYY, 2 RrYY, 1 rrYY, 2 RRYy, 4 RrYy, 2 rrYy, 1 RRyy, 2 Rryy, and 1 rryy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The basis for rejecting any null hypothesis is arbitrary. The researcher can set more or less stringent standards by deciding to raise or lower the \(p\) value used to reject or not reject the hypothesis. In the case of the chi- square analysis of genetic crosses, would the use of a standard of \(p=0.10\) be more or less stringent about not rejecting the null hypothesis? Explain.

Which of Mendel's postulates can only be demonstrated in crosses involving at least two pairs of traits? State the postulate.

Thalassemia is an inherited anemic disorder in humans. Affected individuals exhibit either a minor anemia or a major anemia. Assuming that only a single gene pair and two alleles are involved in the inheritance of these conditions, is thalassemia a dominant or recessive disorder?

A certain type of congenital deafness in humans is caused by a rare autosomal (not X-linked) dominant gene. (a) In a mating involving a deaf man and a deaf woman (both heterozygous), would you expect all the children to be deaf? Explain your answer. (b) In a mating involving a deaf man and a deaf woman (both heterozygous), could all the children have normal hearing? Explain your answer. (c) Another form of deafness is caused by a rare autosomal recessive gene. In a mating involving a deaf man and a deaf woman, could some of the children have normal hearing? Explain your answer.

Dentinogenesis imperfecta is a tooth disorder involving the production of dentin sialophosphoprotein, a bone-like component of the protective middle layer of teeth. The trait is inherited as an autosomal dominant allele located on chromosome 4 in humans and occurs in about 1 in 6000 to 8000 people. Assume that a man with dentinogenesis imperfecta, whose father had the disease but whose mother had normal teeth, married a woman with normal teeth. They have six children. What is the probability that their first child will be a male with dentinogenesis imperfecta? What is the probability that three of their six chil- dren will have the disease?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free