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In a family of six children, where one grandparent on either side has red hair, what mathematical expression predicts the probability that two of the children have red hair?

Short Answer

Expert verified
Answer: The mathematical expression for the probability is 15 × x^2 (1-x)^4, where x represents the probability of a child having red hair and (1-x) represents the probability of a child not having red hair.

Step by step solution

01

Identify the problem type

This exercise is a combination problem, dealing with the probability of having two out of six children with red hair. We will use the binomial coefficient to find the number of different arrangements and compute the probability.
02

Using binomial coefficient

In a family of six children, where one grandparent on either side has red hair, we will use binomial coefficient to find the different combinations of having two children with red hair. The binomial coefficient for finding two successes (red hair) in six trials (children) is denoted by C(6,2) or 6!/[2!(6-2)!].
03

Compute the binomial coefficient

Now, we will compute the binomial coefficient C(6, 2): C(6, 2) = 6!/(2!(6-2)!) = 6!/(2!(4)!) = (6 × 5 × 4 × 3 × 2 × 1)/((2 × 1) × (4 × 3 × 2 × 1)) = (6 × 5)/(2) = 15 So, there are 15 different ways to arrange two children with red hair among the six siblings.
04

Compute the probability expression

Let x represent the probability of a child having red hair. Then, the probability of a child not having red hair is (1-x). Now, we have to compute the probability expression for two of the six children having red hair. For each of these 15 combinations, the probability of two children with red hair and four children without red hair is x^2 (1-x)^4. Since these combinations are mutually exclusive, we should sum the probabilities of each combination: Probability = C(6, 2) × x^2 (1-x)^4 = 15 × x^2 (1-x)^4 This expression represents the probability that two of the six children have red hair in a family where one grandparent on either side has red hair.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
The binomial coefficient, symbolized by the notation C(n, k) or sometimes as choose k, is a fundamental concept in probability and combinatorics, which plays a crucial role in calculating the number of ways 'k' successes can occur in 'n' trials. It's akin to determining how many different combinations of a group can be formed.

For our exercise involving genetics, the binomial coefficient helps us to figure out the various ways two children out of six can inherit a specific trait, like red hair, from their grandparents. The mathematical expression of the binomial coefficient for two successes in six trials is choose 2 which simplifies to 15 combinations after calculation. Each combination represents a unique set of children among the six who could possess the trait in question. Understanding and computing the binomial coefficient is a cornerstone in the study of genetic probability, as it allows us to quantify the patterns in which traits are passed down through generations.

Improving upon this exercise might involve visual aids such as family trees or Punnett squares to enhance the comprehension of how these combinations relate to real-world genetics scenarios.
Inheritance of Traits
In genetics, the inheritance of traits refers to how certain characteristics are transmitted from parents to their offspring through genes. Each parent contributes one allele for every gene, and the combination of these alleles determines the traits of the children. This process is governed by Mendelian inheritance patterns, including dominant and recessive traits.

In the given exercise, having red hair is likely considered a recessive trait, which means a child needs to inherit the red hair allele from both parents to express that phenotype. Our exercise simplifies the situation by not considering the specific odds associated with inheriting the red haired allele; instead, it defines the probability as 'x'. When considering the improvement of students' understanding, it's helpful to explain that genetic traits aren't always a simple matter of dominant or recessive, as some traits are influenced by multiple genes (polygenic) or can exhibit incomplete dominance and co-dominance.

Highlighting real inheritance patterns and how they can deviate from idealized models can provide students with a more nuanced appreciation of genetic variation.
Genetic Probability Calculations
The calculations of genetic probabilities involve determining the likelihood of certain traits appearing in offspring, based on the genetic makeup of their parents. In our exercise, the focus is on finding the probability of having a certain number of children with a trait, given the odds of any one child having that trait.

To do this, we combine our understanding of the binomial coefficient with the laws of probability. We calculate the probability of two children having red hair and four not having it, then multiply the probability of that specific outcome by the number of ways it can occur, which we found to be 15. The resulting expression: \(15 \times x^2(1-x)^4\) builds the foundation for predicting complex genetic outcomes.

For a more intuitive understanding, reiterating the concepts with concrete examples or interactive simulations can significantly help. Engaging with scenarios where probabilities change based on different parental genotypes, or where students can adjust 'x' to see how it affects the outcome, reinforces the relationship between inheritance and probability in a tangible way.

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Most popular questions from this chapter

What is the basis for homology among chromosomes?

Two true-breeding pea plants were crossed. One parent is round, terminal, violet, constricted, while the other expresses the respective contrasting phenotypes of wrinkled, axial, white, full. The four pairs of contrasting traits are controlled by four genes, each located on a separate chromosome. In the \(\mathrm{F}_{1}\) only round, axial, violet, and full were expressed. In the \(\mathrm{F}_{2},\) all possible combinations of these traits were expressed in ratios consistent with Mendelian inheritance. (a) What conclusion about the inheritance of the traits can be drawn based on the \(\mathrm{F}_{1}\) results? (b) In the \(\mathrm{F}_{2}\) results, which phenotype appeared most frequently? Write a mathematical expression that predicts the probability of occurrence of this phenotype. (c) Which \(\mathrm{F}_{2}\) phenotype is expected to occur least frequently? Write a mathematical expression that predicts this probability. (d) In the \(F_{2}\) generation, how often is either of the \(P_{1}\) phenotypes likely to occur? (e) If the \(F_{1}\) plants were testcrossed, how many different phenotypes would be produced? How does this number compare with the number of different phenotypes in the \(\mathrm{F}_{2}\) generation just discussed?

An alternative to using the expanded binomial equation and Pascal's triangle in determining probabilities of phenotypes in a subsequent generation when the parents' genotypes are known is to use the following equation: \(\frac{n !}{s ! t !} a^{s} b^{t}\) where \(n\) is the total number of offspring, \(s\) is the number of offspring in one phenotypic category, \(t\) is the number of offspring in the other phenotypic category, \(a\) is the probability of occurrence of the first phenotype, and \(b\) is the probability of the second phenotype. Using this equation, determine the probability of a family of 5 offspring having exactly 2 children afflicted with sickle-cell anemia (an autosomal recessive disease \()\) when both parents are heterozygous for the sickle-cell allele.

Albinism, lack of pigmentation in humans, results from an autosomal recessive gene (a). Two parents with normal pigmentation have an albino child. (a) What is the probability that their next child will be albino? (b) What is the probability that their next child will be an albino girl? (c) What is the probability that their next three children will be albino?

A certain type of congenital deafness in humans is caused by a rare autosomal (not X-linked) dominant gene. (a) In a mating involving a deaf man and a deaf woman (both heterozygous), would you expect all the children to be deaf? Explain your answer. (b) In a mating involving a deaf man and a deaf woman (both heterozygous), could all the children have normal hearing? Explain your answer. (c) Another form of deafness is caused by a rare autosomal recessive gene. In a mating involving a deaf man and a deaf woman, could some of the children have normal hearing? Explain your answer.

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