Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Two different crosses were set up between carrots (Daucus carota \()\) of different colors and carotenoid content (Santos, Carlos A. F. and Simon, Philipp W. 2002. Horticultura Brasileira 20). Analyses of the \(\mathrm{F}_{2}\) generations showed that four loci are associated with the \(\alpha\) carotene content of carrots, with a broad-sense heritability of \(90 \% .\) How many distinct phenotypic categories and genotypes would be seen in each \(\mathrm{F}_{2}\) generation, and what does a broad-sense heritability of \(90 \%\) mean for carrot horticulture?

Short Answer

Expert verified
Answer: There are 5 distinct phenotypic categories in this carrot population. A broad-sense heritability of 90% means that 90% of the observed variation in alpha carotene content is due to genetic factors, indicating that selective breeding would be effective in increasing the carotene content of the carrots.

Step by step solution

01

Calculate the distinct genotypic categories

To calculate the distinct genotypic categories, we have to consider that each locus can be homozygous dominant (AA), heterozygous (Aa), or homozygous recessive (aa). Since there are 4 loci associated with the trait, the total number of distinct genotypic categories can be calculated using the formula \(3^n\), where n is the number of loci. Hence, the total number of genotypic categories is \(3^4\).
02

Calculate the phenotypic categories

Here we have 4 loci associated with the carotene content, and each locus may have dominant (A) and recessive (a) alleles. The phenotypes depend on these alleles as dominant alleles (A) would lead to higher carotene content, while recessive alleles (a) would lead to lower carotene content. Since we have 4 loci, there could be a phenotypic range from 0 (all recessive alleles) to 4 (all dominant alleles) in steps of 1. Therefore, there are a total of 5 distinct phenotypic categories.
03

Calculate the number of genotypes in each F2 generation

Given that we've found a total of 81 genotypic categories (\((3^4)=81)\), then each F2 generation will have 81 distinct genotypes.
04

Explain the meaning of the broad-sense heritability of 90%

Broad-sense heritability (H2) is a measure of the proportion of phenotypic variance that can be attributed to genetic factors. In this case, the broad-sense heritability of 90% means that 90% of the observed variation in alpha carotene content in the carrot population can be explained by the genetic differences among the carrots. The remaining 10% of the variation is due to environmental factors or interactions between genes and the environment. For carrot horticulture, this high heritability implies that selective breeding will be effective in increasing the carotene content of the carrots, as the majority of the variations are determined by the carrots' genetic constitution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Corn plants from a test plot are measured, and the distribution of heights at \(10-\mathrm{cm}\) intervals is recorded in the following table: $$\begin{array}{cc}\text { Height }(\mathrm{cm}) & \text { Plants (no.) } \\\100 & 20 \\\110 & 60 \\\120 & 90 \\\130 & 130 \\\140 & 180 \\\150 & 120 \\\160 & 70 \\\170 & 50 \\\180 & 40\end{array}$$ Calculate (a) the mean height, (b) the variance, (c) the standard deviation, and (d) the standard error of the mean. Plot a rough graph of plant height against frequency. Do the values represent a normal distribution? Based on your calculations, how would you assess the variation within this population?

A 3 -inch plant was crossed with a 15 -inch plant, and all \(\mathrm{F}_{1}\) plants were 9 inches. The \(F_{2}\) plants exhibited a "normal distribution," with heights of \(3,4,5,6,7,8,9,10,11,12,13,14,\) and 15 inches. (a) What ratio will constitute the "normal distribution" in the \(\mathrm{F}_{2}\) ? (b) What will be the outcome if the \(\mathrm{F}_{1}\) plants are testcrossed with plants that are homozygous for all nonadditive alleles?

If one is attempting to determine the influence of genes or the environment on phenotypic variation, inbred strains with individuals of a relatively homogeneous or constant genetic background are often used. Variation observed between different inbred strains reared in a constant or homogeneous environment would likely be caused by genetic factors. What would be the source of variation observed among members of the same inbred strain reared under varying environmental conditions?

In a series of crosses between two true-breeding strains of peaches, the \(F_{1}\) generation was uniform, producing 30 -g peaches. The \(\mathrm{F}_{2}\) fruit mass ranges from 38 to \(22 \mathrm{g}\) at intervals of \(2 \mathrm{g}\) (a) Using these data, determine the number of polygenic loci involved in the inheritance of peach mass. (b) Using gene symbols of your choice, give the genotypes of the parents and the \(\mathrm{F}_{1}\).

Define the following: (a) polygenic, (b) additive alleles, (c) correlation, (d) monozygotic and dizygotic twins, (e) heritability, (f) \(\mathrm{QTL},\) and \((\mathrm{g})\) continuous variation.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free