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If you performed a PCR experiment starting with only one copy of double- stranded DNA, approximately how many DNA molecules would be present in the reaction tube after 15 cycles of amplification?

Short Answer

Expert verified
Answer: After 15 cycles of PCR amplification, there would be approximately 32,768 DNA molecules present.

Step by step solution

01

Understand the PCR amplification process

Polymerase Chain Reaction (PCR) is a molecular biology technique used to amplify specific DNA regions. In each cycle of PCR, the number of DNA molecules doubles. Therefore, the number of DNA molecules after a certain number of cycles can be calculated using the formula: N = N₀ * 2^n, where N is the final number of DNA molecules, N₀ is the initial number of DNA molecules, and n is the number of cycles.
02

Calculate the number of DNA molecules after 15 cycles

In this exercise, we start with one copy of double-stranded DNA (N₀ = 1) and we want to find out how many DNA molecules there are after 15 cycles (n = 15) of amplification. We can use the formula mentioned in Step 1: N = N₀ * 2^n. Plugging in the values, we get: N = 1 * 2^15.
03

Simplify the expression to find the final number of DNA molecules

Now we just need to evaluate the expression: N = 1 * 2^15 = 2^15. Using a calculator or manually calculating, we get: N = 32,768.
04

Provide the answer

So, after 15 cycles of PCR amplification starting with only one copy of double-stranded DNA, there would be approximately 32,768 DNA molecules present in the reaction tube.

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Most popular questions from this chapter

What roles do restriction enzymes, vectors, and host cells play in recombinant DNA studies? What role does DNA ligase perform in a DNA cloning experiment? How does the action of DNA ligase differ from the function of restriction enzymes?

You have recovered a cloned DNA segment from a vector and determine that the insert is 1300 bp in length. To characterize this cloned segment, you isolate the insert and decide to construct a restriction map, Using enzyme I and enzyme II, followed by gel clectrophoresis, you determine the number and size of the fragments produced by enzymes I and II alone and in combination, as recorded in the following table. Construct a restriction map from these data, showing the positions of the restriction-enzyme cutting sites relative to one another and the distance between them in units of base pairs.

Restriction sites are palindromic, that is, they read the same in the \(5^{\prime}\) to \(3^{\prime}\) direction on each strand of DNA. What is the advantage of having restriction sites organized this way?

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Review the Chapter Concepts list on page \(523 .\) All of these refer to recombinant DNA methods and applications. Write a short essay or sketch a diagram that provides an overview of how recombinant DNA techniques help geneticists study genes.

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