Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write a paragraph describing the abbreviated chemical reactions that summarize RNA polymerase-directed transcription.

Short Answer

Expert verified
Question: Briefly describe the major steps and chemical reactions involved in RNA polymerase-directed transcription. Answer: The RNA polymerase-directed transcription process consists of three major steps: Initiation, Elongation, and Termination. In Initiation, RNA Polymerase binds to the DNA promoter, leading to the reaction: RNA Polymerase + DNA_promoter -> RNA Polymerase-DNA_complex. During Elongation, RNA Polymerase adds complementary RNA nucleotides to the DNA template, represented by the reaction: RNA Polymerase-DNA_complex + NTP -> RNA Polymerase-DNA_complex + RNA_n+1. Termination occurs when RNA Polymerase encounters a termination signal, resulting in the reaction: RNA Polymerase-DNA_complex + Termination_Signal -> RNA Polymerase + DNA + RNA_molecule. This process allows for the synthesis of RNA molecules from a DNA template, enabling gene expression and protein synthesis.

Step by step solution

01

Initiation

In the initiation step, the RNA polymerase enzyme binds to a specific region on the DNA called the promoter. The enzyme then unwinds the two strands of the DNA molecule to expose the template strand that will be used for RNA synthesis. The abbreviated chemical reaction for this step can be written as: RNA Polymerase + DNA_promoter -> RNA Polymerase-DNA_complex
02

Elongation

During the elongation step, the RNA polymerase enzyme moves along the DNA template strand and adds complementary RNA nucleotides by forming phosphodiester bonds. This process continues until the entire RNA molecule is synthesized. The abbreviated chemical reaction for this step can be written as: RNA Polymerase-DNA_complex + NTP (Nucleotide) -> RNA Polymerase-DNA_complex + RNA_n+1 (where n represents the length of the RNA chain)
03

Termination

Finally, in the termination step, the RNA Polymerase reaches a specific termination sequence on the DNA which causes the enzyme to release the newly synthesized RNA molecule and the DNA template. This allows the DNA molecule to rewind and return to its original double helix structure while the RNA molecule is now free for further processing or translation. The abbreviated chemical reaction for this step can be written as: RNA Polymerase-DNA_complex + Termination_Signal -> RNA Polymerase + DNA + RNA_molecule In summary, the RNA polymerase-directed transcription process can be described through a series of abbreviated chemical reactions that involve the initiation, elongation, and termination steps. This process allows for the synthesis of RNA molecules from a DNA template, which is a key step in gene expression and protein synthesis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

M. Klemke et al. (2001) discovered an interesting coding phenomenon in which an exon within a neurologic hormone receptor gene in mammals appears to produce two different protein entities (XL \(\alpha\) s, ALEX). Following is the DNA sequence of the exon's \(5^{\prime}\) end derived from a rat. The lowercase letters represent the initial coding portion for the XL \(\alpha\)s protein, and the uppercase letters indicate the portion where the ALEX entity is initiated. (For simplicity, and to correspond with the RNA coding dictionary, it is customary to represent the noncoding, nontemplate strand of the DNA segment.) \(5^{\prime}-\) gtcccaaccatgcccaccgatcttccgcctgcttctgaagATGCGGGCCCAG (a) Convert the noncoding DNA sequence to the coding RNA sequence. (b) Locate the initiator codon within the XL \(\alpha\) segment. (c) Locate the initiator codon within the ALEX segment. Are the two initiator codons in frame? (d) Provide the amino acid sequence for each coding sequence. In the region of overlap, are the two amino acid sequences the same? (e) Are there any evolutionary advantages to having the same DNA sequence code for two protein products? Are there any disadvantages?

Review the Chapter Concepts list on \(\mathrm{p} .342 .\) These all center around how genetic information is stored in DNA and transferred to RNA prior to translation into proteins. Write a short essay that summarizes the key properties of the genetic code and the process by which \(\mathrm{RNA}\) is transcribed on a DNA template.

What was the initial evidence for the existence of mRNA?

It has been suggested that the present-day triplet genetic code evolved from a doublet code when there were fewer amino acids available for primitive protein synthesis. (a) Can you find any support for the doublet code notion in the existing coding dictionary? (b) The amino acids Ala, Val, Gly, Asp, and Glu are all early members of biosynthetic pathways (Taylor and Coates, 1989 ) and are more evolutionarily conserved than other amino acids (Brooks and Fresco, 2003 ). They therefore probably represent "early" amino acids. Of what significance is this information in terms of the evolution of the genetic code? Also, which base, of the first two, would likely have been the more significant in originally specifying these amino acids? (c) As determined by comparisons of ancient and recently evolved proteins, cysteine, tyrosine, and phenylalanine appear to be late-arriving amino acids. In addition, they are considered to have been absent in the abiotic earth (Miller, 1987 ). All three of these amino acids have only two codons each, while many others, earlier in origin, have more. Is this mere coincidence, or might there be some underlying explanation?

Recent observations indicate that alternative splicing is a common way for eukaryotes to expand their repertoire of gene functions. Studies indicate that approximately 50 percent of human genes exhibit alternative splicing and approximately 15 percent of disease-causing mutations involve aberrant alternative splicing. Different tissues show remarkably different frequencies of alternative splicing, with the brain accounting for approximately 18 percent of such events (Xu et al., 2002 . Nuc. Acids Res. \(30: 3754-3766\) ). (a) Define alternative splicing and speculate on the evolutionary strategy alternative splicing offers to organisms. (b) Why might some tissues engage in more alternative splicing than others?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free