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If the GC content of a DNA molecule is \(60 \%\), what are the molar percentages of the four bases (G, C, T, A)?

Short Answer

Expert verified
Answer: In a DNA molecule with 60% GC content, the molar percentages of the four bases are: - Guanine (G): 30% - Cytosine (C): 30% - Thymine (T): 20% - Adenine (A): 20%

Step by step solution

01

Understand the relationships between the bases in DNA

In a DNA molecule, each base pairs with a complementary base: Guanine (G) pairs with Cytosine (C), and Thymine (T) pairs with Adenine (A). Therefore, the sum of the molar percentages of G and C must be equal to the GC content given, and the sum of the molar percentages of T and A must be equal to the rest of the percentage, which is 100% - GC content.
02

Calculate the sum of molar percentages of T and A

We are given the GC content as 60%. We can now find the sum of the molar percentages of T and A as follows: Sum of T and A molar percentages = 100% - GC content = 100% - 60% = 40%.
03

Divide the sum of molar percentages of G and C equally

Since G pairs with C, their molar percentages should be equal. The GC content is 60%, so we can find the molar percentages of each base by dividing the sum by 2: Molar percentage of G = Molar percentage of C = 60% / 2 = 30%.
04

Divide the sum of molar percentages of T and A equally

Since T pairs with A, their molar percentages should also be equal. The sum of the molar percentages of T and A is 40%, so we can find the molar percentages of each base by dividing the sum by 2: Molar percentage of T = Molar percentage of A = 40% / 2 = 20%.
05

State the molar percentages of all four bases

The molar percentages for the four bases in the given DNA molecule are: - Guanine (G): 30% - Cytosine (C): 30% - Thymine (T): 20% - Adenine (A): 20%

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Most popular questions from this chapter

What is the physical state of DNA following denaturation?

Electrophoresis is an extremely useful procedure when applied to analysis of nucleic acids as it can resolve molecules of different sizes with relative ease and accuracy. Large molecules migrate more slowly than small molecules in agarose gels. However, the fact that nucleic acids of the same length may exist in a variety of conformations can often complicate the interpretation of electrophoretic separations. For instance, when a single species of a bacterial plasmid is isolated from cells, the individual plasmids may exist in three forms (depending on the genotype of their host and conditions of isolation): superhelical/supercoiled (form I), nicked/open circle (form \(\mathrm{II}\) ), and linear (form III). Form I is compact and very tightly coiled, with both DNA strands continuous. Form II exists as a loose circle because one of the two DNA strands has been broken, thus releasing the supercoil. All three have the same mass, but each will migrate at a different rate through a gel. Based on your understanding of gel composition and DNA migration, predict the relative rates of migration of the various DNA structures mentioned above.

What evidence did Watson and Crick have at their disposal in 1953? What was their approach in arriving at the structure of DNA?

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