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Next, use the Hardy-Weinberg equation (p2 + 2pq + q2 = 1) to calculate the day seven expected frequencies of genotypes CGCG, CGCY, and CYCY for a population in Hardy-Weinberg equilibrium.

Short Answer

Expert verified

The expected frequencies of the genotypes \({C^G}{C^G}\),\({C^G}{C^Y}\), and \({C^Y}{C^Y}\)calculated from the day seven data are 0.23, 0.50, and 0.26, respectively.

Step by step solution

01

Hardy-Weinberg equilibrium

The mathematical equation for Hardy-Weinberg equilibrium is-

\({p^2} + 2pq + {q^2} = 1\), where \({p^2}\) is the genotype frequency for the homozygous dominant character, \({q^2}\) is the genotype frequency for the homozygous recessive character, and \(2pq\) is the genotype frequency for heterozygous individuals.

And \(p + q = 1\) , where \(p\)is the frequency of the dominant allele, and\(q\)is the frequency of the recessive allele.

A Hardy-Weinberg population is large where random mating occurs and is devoid of natural selection, mutation, and migration influences. In short, the population is not undergoing evolution.

02

Expected genotype frequency

Expected genotype frequency for homozygous dominant genotype and homozygous recessive genotype are the squares of dominant allele frequency and recessive allele frequency, respectively.

For heterozygous dominant genotype, the expected genotype frequency is two times the frequency of dominant and recessive alleles. It provides a measure of the number of a particular genotype that is predicted after a cross.

03

Expected frequencies of genotypes CGCG, CGCY, and CYCY

From the observed frequencies from Day 7, it is given that:

Number of homozygous dominant or green seedlings (\({C^G}{C^G}\))= 49

Total number of seedlings= 216

The genotypic frequency of \({C^G}{C^G}\) (\({p^2}\)) is:

\({p^2} = \frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}dominant{\rm{ }}or{\rm{ }}green{\rm{ }}seedlings{\rm{ }}\left( {{C^G}{C^G}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}\)


The allele frequency for\({C^G}\)allele (\(p\)) is:

\(p = \sqrt {\frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}dominant{\rm{ }}or{\rm{ }}green{\rm{ }}seedlings{\rm{ }}\left( {{C^G}{C^G}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}} \)

\(\begin{aligned}{c}p &= \sqrt {\frac{{49}}{{216}}} \\ &= 0.476\\ \simeq 0.48\end{aligned}\)

The expected genotypic frequencyof \({C^G}{C^G}\) (\({p^2}\)) is:

\(\begin{aligned}{l}{p^2} &= 0.48 \times 0.48\\{p^2} &= 0.23\end{aligned}\)

From the observed frequencies from Day 7, it is given that:

Number of homozygous dominant or yellow seedlings (\({C^Y}{C^Y}\))= 56

Total number of seedlings= 216

The genotypic frequency of \({C^Y}{C^Y}\) (\({q^2}\)) is:

\({q^2} = \frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}recessive{\rm{ }}or{\rm{ }}yellow{\rm{ }}seedlings{\rm{ }}\left( {{C^Y}{C^Y}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}\)

The allele frequency for\({C^Y}\)allele (\(q\)) is:

\(q = \sqrt {\frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}recessive{\rm{ }}or{\rm{ }}yellow{\rm{ }}seedlings{\rm{ }}\left( {{C^Y}{C^Y}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}} \)

\(\begin{aligned}{c}q &= \sqrt {\frac{{56}}{{216}}} \\ &= 0.509\\ \simeq 0.51\end{aligned}\)

The expected genotypic frequencyof \({C^Y}{C^Y}\) (\({q^2}\)) is:

\(\begin{aligned}{l}{q^2} &= 0.51 \times 0.51\\{q^2} &= 0.26\end{aligned}\)

We have:

\(p = 0.48\)and\(q = 0.51\)

The expected frequency for\({C^G}{C^Y}\)(\(2pq\)) is:

\(\begin{aligned}{l}2pq &= 2 \times 0.48 \times 0.51\\2pq &= 0.489\\2pq &= 0.49\end{aligned}\)

\(2pq = 0.5\)

Thus, the expected frequencies of the genotypes such as\({C^G}{C^G}\),\({C^G}{C^Y}\), and\({C^Y}{C^Y}\)are 0.23, 0.50, and 0.26, respectively.

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Most popular questions from this chapter

There are 25 individuals in population 1, all with genotypeAA, and there are 40 individuals in population 2, all with genotypeaa. Assume that these populations are located far from each other and that their environmental conditions are very similar. Based on the information given here, the observed genetic variation most likely resulted from

(A) genetic drift.

(B) gene flow.

(C) nonrandom mating.

(D) directional selection.

In what sense is natural selection more โ€œpredictableโ€ than genetic drift?

Consider a population in which heterozygotes at a certain locus have an extreme phenotype (such as being larger than homozygotes) that confers a selective advantage. Compare this description to the models of selection modes shown in Figure 23.13. Does this situation represent directional, disruptive, or stabilizing selection? Explain your answer.

Heterozygotes at the sickle-cell locus produce both normal and abnormal (sickle-cell) hemoglobin (see Concept 14.4). When hemoglobin molecules are packed into a heterozygote's red blood cells, some cells receive relatively large quantities of abnormal hemoglobin, making these cells prone to sickling. In a short essay (approximately 100โ€“150 words), explain how these molecular and cellular events lead to emergent properties at biological organization's individual and population levels.

If the nucleotide variability of a locus equals 0%, what is the gene variability and number of alleles at that locus?

(A) gene variability = 0%; number of alleles = 0

(B) gene variability = 0%; number of alleles = 1

(C) gene variability = 0%; number of alleles = 2

(D) gene variability 7 0%; number of alleles = 2

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