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A wild-type fly (heterozygous for gray body and normal wings) is mated with a black fly with vestigial wings. The offspring have the following phenotypic distribution: wild type, 778; black vestigial; 785; black normal, 158; gray vestigial, 162. What is the recombination frequency between these genes for the body color and wing size? Is this consistent with the results of the experiment in Figure 15.9?

Short Answer

Expert verified

17% of recombination exists between the genes for the body color and wing size.

Yes, the recombination frequency is consistent with the experiment results, as the recombination frequency obtained in the experiment was also 17%.

Step by step solution

01

Recombination frequency

The measure of recombinant offspring obtained in a genetic cross concerning the number of offspring produced is called recombination frequency. The recombination frequency between gene pairs helps to calculate the distance between the genes on a chromosome.

The following formula calculates the recombination frequency between gene pairs:\({\rm{Recombination frequency}}\,{\rm{ = }}\frac{{{\rm{Number of recombinants}}}}{{{\rm{Total number of offsprings}}}}\,{\rm{ \times 100}}\)

02

Recombination frequency between genes for the body color and wing size

Four types of offspring were obtained from the cross. These were wild type, black vestigial, black normal, and gray vestigial. Wild type and black vestigial are wild type offspring, while black normal and gray vestigial are recombinants obtained from the cross.

The total number of offspring produced in the cross is \({\rm{778 + 785 + 158 + 162 = 1883}}\).

The total number of recombinants is \({\rm{162 + 158 = 320}}\).

The recombination frequency is calculated by substituting the values into the following equation:

\({\rm{Recombination frequency}}\,{\rm{ = }}\frac{{320}}{{1883}}\,{\rm{ \times 100}}\)

\(\begin{aligned}{l}{\rm{Recombination frequency}}\, = \,16.99\,\% \\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \approx 17\% \end{aligned}\)

Thus, the recombination frequency between the genes for the body color and wing size is approximately 17%.

03

Explanation for consistency with the experiment result

In the testcross performed in the experiment, between the body color and wing size, the recombination frequency obtained was 17%. It is consistent with the result of the cross here, as the recombination frequency obtained is also 17%.

The consistency is expected because the same genes were considered in both the experiment and the cross. The distance between the genes does not change from one cross to the other.

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Most popular questions from this chapter

Crossing over is thought to be evolutionarily advantageous because it continually shuffles genetic alleles into novel combinations. Until recently, it was thought that the genes on the Y chromosome might degenerate because they lack homologous genes on the X chromosome with which to pair up prior to crossing over. However, when the Y chromosome was sequenced, eight large regions were found to be internally homologous to each other, and quite a few of the 78 genes represent duplicates. (Y chromosome researcher David Page has called it a "hall of mirrors.โ€). Explain what might be a benefit of these regions.

A man with hemophilia (a recessive, sex-linked condition) has a daughter without the condition. She marries a man who does not have hemophilia. What is the probability that their daughter will have hemophilia? Their son? If they have four sons, what is the probability that all will be affected?

Review the description of meiosis (see Figure 13.8) and Mendelโ€™s laws of segregation and independent assortment (see Concept 14.1). What is the physical basis for each of Mendelโ€™s laws?

Gene A, B, and C are located on the same chromosome. Test crosses show that the recombination frequency between A and B is 28% and that between A and C is 12%. Can you determine the linear order of these genes?

For each type of offspring of the test-cross in Figure 15.9, explain the relationship between its phenotype and the alleles contributed by the female parent. (It will be useful to draw out the chromosomes of each fly and follow alleles throughout the cross.)

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