Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

For each type of offspring of the test-cross in Figure 15.9, explain the relationship between its phenotype and the alleles contributed by the female parent. (It will be useful to draw out the chromosomes of each fly and follow alleles throughout the cross.)

Short Answer

Expert verified

The female parent contributes the alleles, and the male parent contributes recessive alleles. The contribution made by the female parent determines the offspring's phenotype.

Step by step solution

01

Description of offspring

Offspring is the young one of the organism. In sexual reproduction, the fusion of male and female gametes results in the formation of gametes. The offspring produced from sexual reproduction tends to possess the character of parents.

02

Description of the dominant and recessive allele

An allele is a variant present in the gene. The recessive allele is the allele that masks its effect. The other type of allele is the dominant alleles that get expressed in the offspring.

03

Allelic expression in the phenotype

The phenotype of the test crossing produced offspring such as wild type (gray normal), black vestigial, gray vestigial, and black normal. Out of these offspring, only female characters are more prominently seen in these offspring.

The male characters are recessive alleles, so the expression is not prominent. The alleles that are found in the eggs are exposed to the phenotype of the organism.

Hence, the female characters are predominantly seen in the test cross.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume you are mapping genes A, B, C, and D in Drosophila. You know that these genes are linked on the same chromosome, and you determine the recombination frequencies between each pair of genes to be as follows: A-B, 8%; A-C, 28%; A-D, 25%; B-C, 20%; B-D, 33%.

  1. Describe how you determined the recombination frequency for each pair of genes.

  2. Draw a chromosome map based on your data.

Review the description of meiosis (see Figure 13.8) and Mendelโ€™s laws of segregation and independent assortment (see Concept 14.1). What is the physical basis for each of Mendelโ€™s laws?

A wild-type fly (heterozygous for gray body and normal wings) is mated with a black fly with vestigial wings. The offspring have the following phenotypic distribution: wild type, 778; black vestigial; 785; black normal, 158; gray vestigial, 162. What is the recombination frequency between these genes for the body color and wing size? Is this consistent with the results of the experiment in Figure 15.9?

A planet is inhabited by creatures that reproduce with the same hereditary patterns seen in humans. Three phenotypic characters are height (T = tall, t= dwarf), head appendages (A = antennae, a = no antennae), and nose morphology (S = upturned snout, s = downturned snout). Since the creatures are not โ€œintelligent,โ€ Earth scientists are able to do some controlled breeding experiments using various heterozygotes in testcrosses. For tall heterozygotes with antennae, the offspring are tall antennae, 46; dwarf antennae, 7; dwarf no antennae, 42; tall no antennae, 5. For heterozygotes with antennae and an upturned snout, the offspring are antennae upturned snout 47; antennae downturned snout, 2; no antennae downturned snout, 48; no antennae upturned snout, 3. Calculate the recombination frequencies for both experiments.

Reciprocal cross between two primrose varieties, A and B, produced the following results: Afemaleร—Bmaleโ†’offspringwith all green (non-variegated) leaves;Bfemaleร—Amaleโ†’offspring with patterned (variegated) leaves. Explain these results

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free