Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Compare the roles of tubulin and actin during eukaryotic cell division with the roles of tubulin-like and actin-like proteins during bacterial binary fission.

Short Answer

Expert verified

Tubulin is the protein that is involved in the development of the spindle fibers and in the displacement of the chromosomes. The actin is also a protein that mainly functions during cell division.

In the case of bacterial division, the functions of both actin and tubulin differ, and it reverses eukaryotic cell division. The actin protein helps in the movement of chromosome in the prokaryotic cell in the opposite direction, while tubulin protein help in the division of the cell.

Step by step solution

01

Tubulin protein

Tubulin protein works as a skeletal system of the cell. The microtubule remains flexible because of the presence of tubulin. This tubulin protein polymerizes to form hollow fibers. The alpha and beta-tubulin support the segregation of DNA.

02

Actin protein

The actin protein gets deconstructed prior to the division of the cell. The stable actin molecule helps in rearranging the microtubule network. Contractile rings are formed of actin filament that helps in separating the daughter cells.

03

Bacterial binary fission

In binary fission of the bacterial cells, there is polymerization of the actin protein molecules; these molecules help in the division of the bacterial cells into two parts. Both the bacterial cells are divided into two parts having the same chromosome as that of the parent cell.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The decline of MPF activity at the end of mitosis is due to

(A) the destruction of the protein kinase CDK.

(B) decreased synthesis of Cdk.

(C) degradation of cyclin

(D) accumulation of cyclin.

The result of mitosis is that the daughter cells end up with the same number of chromosomes that the parent cell had. Another potential way to maintain the number of chromosomes would be to carry out cell division first and then duplicate the chromosomes in each daughter cell. Assess whether this would be an equally good way of organizing the cell cycle. Explain why evolution had not led to this alternative.

The histogram representing the treated sample shows the effect of growing the cancer cells alongside human umbilical cord stem cells that produce the potential inhibitor. (a) Label the histogram with the cell cycle phases. Which phase of the cell cycle has the greatest number of cells in the treated sample? Explain. (b) Compare the distribution of cells among G1, S, and G2 phases in the control and treated samples. What does this tell you about the cells in the treated sample? (c) Based on what you learned in Concept 12.3, propose a mechanism by which the stem cell-derived inhibitor might arrest the cancer cell cycle at this stage. (More than one answer is possible.)

The drug cytochalasin B blocks the function of actin. Which of the following aspects of the animal cell cycle would be most disrupted by cytochalasin B?

(A) Spindle formation

(B) Spindle attachment to kinetochores

(C) Cell elongation during anaphase

(D) Cleavage furrow formation and cytokinesis

One difference between cancer cells and normal cells is that cancer cells

(A) are unable to synthesize DNA.

(B) are arrested at the S phase of the cell cycle.

(C) continue to divide even when they are tightly packed together.

(D) cannot function properly because they are affected by density-dependent inhibition.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free