Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

First, make sure you understand how to read the comparison matrix.

Find the cell that represents the comparison of C. testosteroniandE. coli. What value is given in this cell? What does that value signifyabout the comparable rRNA gene sequences in those two organisms?Explain why some cells have a dash rather than a value. Whyare some cells shaded gray, with no value?

Wheat mitochondrion

A. tumefaciens

C. testosteroni

E. coli

M. capricolum

A. nidulans

Wheat mitochondrion

-

48

38

35

34

34

A. tumefacians

-

55

57

52

53

C. testosterone

-

61

52

52

E. coli

-

48

52

M. capricolum

-

50

A. nidulans

-

Short Answer

Expert verified

Bacteria are microorganisms that are unicellular in nature and belong to the class of prokaryotic organisms. According to the given data, the cell that represents the comparison of C. testosteroni and E. coli is 61. This value indicates that 61 per cent of the 617 nucleotide positions are the same in both species.

Some other cells have dash other than the value because those cells would compare one species to itself. Some cells shaded gray with no value because those cells would duplicate comparisons shown elsewhere in the matrix.

Step by step solution

01

Types of bacteria

Bacteria are microorganisms that can be seen everywhere, from extreme to normal temperatures. Based on shape, there are different types of bacteria like bacilli, cocci, and vibrio.

02

Use of Comparison Matrix

As the name suggests, a comparison matrix is a tabular representation between different species that shows similarities and differences between them. It is used to find the relationship between organisms by comparing them with each other.

03

Step 3: C. testosteroni and E. coli

Comamonas testosteroniis a bacterium that belong to family Comamonadaceae.This bacteria is gram-negative in nature. They can live in a wide range of habitats such as water and soil. Escherichia coli is a bacterium that belongs to the family Enterobacteriaceae and is gram-negative in nature.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the three life cycles in Figure 13.6 exhibits alternation of generations? How does it differ from the other two?

In a life cycle with alternation of generations, multicellular haploid forms alternate with

(A) unicellular haploid forms

(B) unicellular diploid forms

(C) multicellular haploid forms

(D) multicellular diploid forms.

MAKE CONNECTIONS The bacterium Wolbachia is a symbiont that lives in mosquito cells and spreads rapidly through mosquito populations. Wolbachia can make mosquitoes resistant to infection by Plasmodium; researchers are seeking a strain that confers resistance and does not harm mosquitoes. Compare evolutionary changes that could occur if malaria control is attempted using such a Wolbachia strain versus using insecticides to kill mosquitoes. (Review Figure 28.16 and Concept 23.4.)

The equation F = e-kt describes the fraction F of an original isotope remaining after a period of t years; the exponent is negative because it refers to a decrease over time. The constant k provides a measure of how rapidly the original isotope decays. For the decay of carbon-14 to nitrogen-14, k = 0.00012097. To find t, rearrange the equation by following these steps: (a) Take the natural logarithm of both sides of the equation: ln(F ) = ln(e-kt). Rewrite the right side of this equation by applying the following rule: ln(ex) = x ln(e). (b) Since ln(e) = 1, simplify the equation. (c) Now solve for t and write the equation in the form โ€œt = ________.โ€

Summarize the role of endosymbiosis in eukaryotic evolution.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free