Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The scientists mapping the SNPs in the human genome noticed that groups of SNPs tended to be inherited together, in blocks known as haplotypes, ranging in length from 5,000 to 200,000 base pairs. There are as few as four or five commonly occurring combinations of SNPs per haplotype. Integrating what you’ve learned throughout this chapter and this unit, propose an explanation for this observation.

Short Answer

Expert verified

The0.1% difference in the DNA sequence is the reason behind the inherited phenotypic variation in the genome of the human species.

Step by step solution

01

Inheritance

Whenthe generation of one species acquires alleles from its previous generation, they are studied by a biological principle involving genetics (study heredity). This is known as inheritance.

Various inheritance patterns are co-dominant, mitochondrial, autosomal dominant, and autosomal recessive inheritance. Some common examples of inherited characteristics are disease susceptibility, eye color, and hair color.

02

Haplotype

The linked SNPs (single nucleotide polymorphisms) pattern inherited within a living organism together from their parents and located on the same chromosome is called haplotype or haploid genotype.

The MHC (major histocompatibility complex) comprises the HLA allele. It is an example of a haplotype. Each of the parent individuals provides a single haplotype (pair of DNA variation) to each offspring.

03

Explanation for observation

SNPs mapping is a methodology performed to map genes or find out the exact location of the gene on a specific chromosome.

This methodology (SNPs or single nucleotide polymorphism) is essential to identify the site where the DNA sequence has variations or SNP variants.

The SNPs (base-pair difference at a specific site in the genome) contribute to the changes in phenotypic traits, such as height, weight, and eye color within organisms like the human population.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assign each DNA segment at the top of Figure 18.8 to a sector in the pie chart in Figure 21.6.

Below are the amino acid sequences (using the single-letter code; see Figure 5.14) of four short segments of the FOXP2 protein from six species: chimpanzee (C), orangutan (O), gorilla (G), rhesus macaque (R), mouse (M), and human (H). These segments contain all of the amino acid differences between the FOXP2 proteins of these species.

Use a highlighter to color any amino acid that varies among the species. (Color that amino acid in all sequences.)

  1. The C, G, R sequences are identical. Identify which lines correspond to those sequences.
  2. The H sequence differs from that of the C, G, R species at two amino acids. Underline the two differences in the H sequence.
  3. The O sequence differs from the C, G, R sequences at one amino acid (having V instead of A) and from the H sequence at three amino acids. Identify the O sequence.
  4. In the M sequence, circle the amino acid(s) that differ from the C, G, R sequences, and draw a square around those that differ from the H sequence.
  5. Primates and rodents diverged between 60 and 100 million years ago, and chimpanzees and humans about 6 million years ago. Compare the amino acid differences between the mouse and the C, G, R species with those between the human and the C, G, R species. What can you conclude?

Describe the whole-genome shotgun approach.

Make an ordered list of all the percent identity values from the table, starting with 100% at the top. Next to each number write the globin pair(s) with that percent identity value. Use one color for the globins from the α family and a different color for the globins from the β family. (a) Compare the order of pairs on your list with their positions in the model shown in Figure 21.14. Does the order of pairs describe the same relative “closeness” of globin family members seen in the model? (b) Compare the percent identity values for pairs within the α or β group to the values for between-group pairs.

In Concept 20.2, you learned about genome-wide association studies. Explain how these studies use the systems biology approach.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free