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What enables RNA polymerase to start transcribing a gene at the right place on the DNA in a bacterial cell? In a eukaryotic cell?

Short Answer

Expert verified

In the prokaryotic cell, RNA polymerase binds to the promoter segment directly and initiates the process of transcription.

In a eukaryotic cell, transcription factors bind to the promoter region, followed by the binding of the RNA polymerase to the promoter region to initiate the transcription process.

Step by step solution

01

Description of RNA polymerase

RNA polymerase is the enzyme that synthesizes DNA from the RNA strand. It mediates the critical process in gene expression, such as transcription.

02

RNA polymerase binding in the bacterial cell

Bacteria are single-celled prokaryotic organisms. The transcription process occurs more simply in bacteria compared to eukaryotes.

The RNA polymerase enzyme recognizes the promoter region directly and binds to it to begin the transcription process. There is no requirement for transcription factors in the prokaryotic cells.

03

RNA polymerase binding in the eukaryotic cell

Eukaryotic cells have complex organization compared to prokaryotic cells.The transcription factors are the assisting elements that facilitate the binding of the RNA polymerase with the promoter sequence. In this process, there is no direct binding involved.

The transcription factors have eligibility to control the rate of the transcription process.

Hence, the RNA polymerase itself searches for the promoters and binds to them in the case of the bacterial cell. In the eukaryotic cell, the transcription factors enable the binding of the promoter with the RNA polymerase.

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Most popular questions from this chapter

The template strand of a gene contains the sequence 3โ€™-TTCAGTCGT-5โ€™. Imagine that the non-template plate sequence was transcribed instead of the template sequence. Draw the mRNA sequence and translate it using Figure 17.6. (Be sure to pay attention to the 5โ€™ and 3โ€™ ends.) Predict how well the protein synthesized from the non-template strands would function, if at all.

Draw a tRNA with the anticodon 3โ€™-CGU-5โ€™. What two different codons could it bind to? Draw each codon on an mRNA, labeling all 5โ€™ and 3โ€™ ends, the tRNA, and the amino acid it carries.

Evolution accounts for the unity and diversity of life, and the continuity of life is based on heritable information in the form of DNA. In a short essay (100-150words), discuss how the fidelity with which DNA is inherited is related to the processes of evolution. (Review the discussion of proofreading and DNA repair in Concept 16.2)

In the sequence logo (bottom, left), the horizontal axis shows the primary sequence of the DNA by nucleotide position. Letters for each base are stacked on top of each other according to their relative frequency at that position among the aligned sequences, with the most common base as largest letter at the top of the stack. The height of each letter represents the relative frequency of that base at that position. (a) In the sequence alignment, count the number of each base at position-9 and order them from the most to least frequent. Compare this to the size and placement of each base -9 in the logo. (b) Do the same for position 0 and 1.

The anticodon of a particular tRNA molecule is:

  1. complementary to the corresponding mRNA codon.

  2. complementary to the corresponding triplet in rRNA.

  3. the part of tRNA that bonds to a specific amino acid.

  4. catalytic, making the tRNA a ribozyme.

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