Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question: Which metabolic pathway is common to both fermentation and cellular respiration of a glucose molecule?

  1. the citric acid cycles
  2. the electron transport chain
  3. glycolysis
  4. reduction of pyruvate to lactate

Short Answer

Expert verified
  1. The statement "the citric acid cycle" is false.
  2. The statement "the electron transport chain" is false
  3. The word "glycolysis" is true.
  4. The statement "reduction of pyruvate to lactate." is false.

Step by step solution

01

Metabolic pathways

Metabolic pathways are the chemical reaction that takes place within the human body for survival and reproduction.

Prokaryotic organism undergoes an easier metabolic process compared to eukaryotic organism. Eukaryotic organisms have a complex body organization.

02

Explanation of option '(A)'

The citric acid cycle does not involve the glucose molecule. Instead, the major metabolite of this process is the acetyl CoA. In the process, carbon dioxide is released as a product.

Thus, the citric acid cycle is not the common metabolic pathway for cellular respiration and the fermentation of glucose.

Therefore, the given statement is false

03

Explanation of option '(B)'

The electron transport chain is the mechanism by which the electrons are shifted to oxygen. It is a series of reaction that releases energy. The primary work of the electron transport chain is involved in making ATP.

Thus, the electron transport chain is not the common metabolic pathway of cellular respiration and fermentation.

Therefore, the given statement is false.

04

Explanation of option '(C)'

Pyruvate is the end product that is formed from glycolysis. The body utilizes this pyruvate molecule in ways such as cellular respiration and fermentation.

The cellular respiration takes place in oxygen, followed by a series of reactions after glycolysis, such as the Krebs cycle and electron transport chain. Fermentation is the process by which the pyruvate is converted into ethanol or lactate.

Thus, glycolysis is the common metabolic pathway for cellular respiration and fermentation.

Therefore, the given statement is true.

05

Explanation of option '(D)'

The conversion of pyruvate to lactate happens in the absence of oxygen. This process is the mechanism of fermentation.

Thus, converting pyruvate to lactate is not the only fate of glucose that undergoes the glycolysis mechanism.

Therefore, the given statement is false.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Step 3 in Figure 9.9 is a significant point of regulation of glycolysis. ATP and related molecules allosterically regulate the enzyme phosphofructokinase (see Concept 8.5). Considering the overall result of glycolysis, would you expect ATP to inhibit or stimulate the activity of this enzyme? Explain. (Hint: Make sure you consider the role of ATP as an allosteric regulator, not as a substrate of the enzyme.)

Question: When electrons flow along the electron transport chain of mitochondria, which of the following changes occurs?

  1. The pH of the matrix increases.
  2. ATP synthase pumps protons by active transport.
  3. The electrons gain free energy.
  4. NAD+ is oxidized

The variation found in a set can be estimated by the standard deviation, s:

\({s_x}\, = \sqrt {\frac{1}{{n - 1}}} \sum {({x_i}} - \,\overline x {)^2}\)

Calculate the standard deviation for each treatment.

Treatment

Dose (mg/kg)

Log of number of colonies

Mean (\(\overline x \,\))

\({x_i}\, - \,\overline x \)

Control

-

9.0,9.5,9.0,8.9

9.1

(-0.1), 0.4, (-0.1), (-0.2)

Vancomycin

1.0

8.5,8.4,8.2

8.36

0.14, 0.04, (-0.16)

5.0

5.3,5.9,4.7

5.3

0, 0.6, (-0.6)

Teixobactin

1.0

8.5,6.0,8.4,6.0

7.22

1.28, (-1.22), 1.18, (-1,22)

5.0

3.8,4.9,5.2,4.9

4.7

(-0.9), 0.2,0.5, 0.2

Which of the following strategies would most rapidly increase the genetic diversity of a population in an extinction vortex?

(A) Establish a reserve that protects the populationโ€™s habitat.

(B) Introduce new individuals transported from other populations of the same species.

(C) Sterilize the least fit individuals in the population.

(D) Control populations of the endangered populationโ€™s predators and competitors.

How does the reduced genetic diversity of small populations make them more vulnerable to extinction?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free