Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which two pairs of molecules in Figure 4.5 are isomers? For each pair, identify the type of isomer.

Short Answer

Expert verified

The forms C4H10 in (b) and butenes in (c) (forms of C4H8) are isomers.

They are structural isomers of chain and structural isomers of position, respectively.

Step by step solution

01

Introduction to isomers

The organic structures formed by carbon, hydrogen, and oxygen are called hydrocarbons. Examples of hydrocarbons include alkanes, alkene, alkynes, aldehydes, carboxylic acids, urea, etc. Carbon dioxide is not a hydrocarbon as it does not contain a hydrogen atom.

Isomers are molecules with similar molecular formulas but different structural formulas. Isomers can have some differences in their functions too.

02

Types of isomers

Isomers are compounds whose molecular formulas resemble each other but have a different arrangement of atoms, due to which they become two separate structures. Thus, there is also a difference in their properties. The isomers are of two main typesโ€”structural isomers and cis-trans isomers.

Structural isomers are compounds with the same number of carbon atoms but different arrangements. They are furthercategorized as Chain isomerism, Position isomerism, Functional group isomerism, Metamerism, and Tautomerism.

Cis-trans isomers have the functional groups on the same side of isomers (cis isomers) or on the opposite side(trans isomers).

03

Structural isomers

Most of the organic molecules have a carbon skeleton.Structural isomers are compounds that differ in the covalent arrangements of their atoms.The carbon skeleton is straight in one compound but may be branched-chain in another compound. The number of chances of forming isomers increases as carbon skeletons increase in size.

Fig 4.5 (b) shows isomers having the molecular formula C4H10.

Here one compound has four carbon atoms in the parent chain, and Hydrogen atoms share the free electrons. In contrast, the other has three carbon atoms with a branch at C2.

In fig 4.5 (c), the first is a butene with double bonds at C1 while the second is a butene with double bonds at C2.

04

Types of Isomers

The first pair in figure 4.5 (b) is a pair of chain isomers as they differ in the parent carbon chain. The second pair in figure 4.5 (c) is a pair of position isomers because the difference in position of the double bond in each figure makes them structural isomers.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The synthesis of products is limited by the amount of reactants. (a) If one mole each of CH4, NH3, H2S, and CO2 is added to \({\bf{1}}\) liter of water in a flask, how many moles of hydrogen, carbon, oxygen, nitrogen, and sulfur are in the flask?

(b) Looking at the molecular formula in the table, how many moles of each element would be needed to make \({\bf{1}}.{\bf{0}}\) mole of glycine?

(c) What is the maximum number of moles of glycine that could be made in that flask, with the specified ingredients, if no other molecules were made? Explain.

(d) If serine or methionine were made individually, which element(s) would be used up first for each? How much of each product could be made?

What chemical change occurs to ATP when it reacts with water and releases energy?

See Figures 4.5a and 4.7. Can propane (C3H8) form isomers? Explain.

Identify the asymmetric carbon in this molecule:

In 1918, an epidemic of sleeping sickness caused an unusual rigid paralysis in some survivors, similar to symptoms of advanced Parkinsonโ€™s disease. Years later, L-dopa (below, left), a chemical used to treat Parkinsonโ€™s disease, was given to some of these patients. L-dopa as remarkably effective at eliminating the paralysis, at least temporarily. However, its enantiomer, D-dopa (right), was subsequently shown to have no effect at all, as is the case for Parkinsonโ€™s disease. In a short essay (100-150 words), discuss how the effectiveness of one enantiomer and not the other illustrates the theme of structure and function.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free