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Question: If an enzyme is added to a solution where its substrate and product are in equilibrium, what will occur?

  1. Additional substrate will be formed.
  2. The reaction will change from endergonic to exergonic.
  3. The free energy of the system will change.
  4. Nothing; the reaction will stay at equilibrium.

Short Answer

Expert verified
  1. The option "Additional substrate will be formed" is false.
  2. The option "The reaction will change from endergonic to exergonic" is false.
  3. The option "The free energy of the system will change" is false.
  4. The option "Nothing; the reaction will stay at equilibrium" is true.

Step by step solution

01

Meaning of enzymes

Enzymes are biocatalysts produced by living organisms. They are known as agents of life as they accelerate chemical reactions. These function in aqueous solution under mild pH and temperature conditions.

02

Explanation of option (A)

Substrates are molecules that bind to the enzymes' active site during catalysis and lead to the formation of the product.

Thus, the addition of enzymes would not lead to the formation of the excess substrate. This is because substrates for enzymes are added at the beginning of the reaction along with enzymes to obtain the desired product.

Therefore, the given option is false.

03

Explanation of option (B)

Endergonic reactions are catalyzed by enzymes by linking them to exergonic processes. Enzymes accelerate the rate of reaction but adding enzymes will not change the reaction from endergonic to exergonic.

Therefore, the given option is false.

04

Explanation of option (C)

Free energy refers to the amount of energy associated with a system.The free energy change of a reaction is denoted as ฮ”G. Enzymes lower the activation energy and speed up the reaction, but they do not affect the free energy of a reaction.

Thus, adding an enzyme would not change the system's free energy as it remains the same.

Therefore, the given option is false.

05

Explanation of option (D)

At equilibrium of a chemical reaction, the substrate concentration is equal to the concentration of the product. This means the rate of forward and backward reactions would be the same.However, enzymes cannot affect the equilibrium state of a reaction.

The equilibrium only depends on the initial concentration of substrates, and adding enzymes would not affect the equilibrium state of the reaction.

Thus, the reaction will stay at equilibrium.

Therefore, the given option is true.

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Most popular questions from this chapter

Some nighttime partygoers wear glow-in-the-dark necklaces. The necklaces start glowing once they are โ€œactivatedโ€ by snapping the necklace in a way that allows two chemicals to react and emit light in the form of chemiluminescence. Is the chemical reaction exergonic or endergonic? Explain your answer.

Question: Most cells cannot harness heat to perform work because

  1. heat does not involve a transfer of energy
  2. cells do not have much thermal energy; they are relatively cool
  3. temperature is usually uniform throughout a cell
  4. heat can never be used o do work

A mature lysosome has an internal pH of around 4.5. Using Figure 8.17b as a guide, draw a graph showing what you would predict for a lysosomal enzyme's reaction rate. Label its optimal pH, assuming its optimal pH matches its environment.

Question: If an enzyme in solution is saturated with substrate, the most effective way to obtain a faster yield of products is to

  1. add more of the enzyme
  2. heat the solution to 90ยฐC.
  3. add more substrate
  4. add a non-competitive inhibitor

Question: Using a series of arrows, draw the branched metabolic reaction pathway described by the following statements, and then answer the question at the end. Use red arrows and minus signs to indicate inhibition.

L can form either M or N.

M can form O.

O can form either P or R.

P can form Q.

R can form S.

O inhibits the reaction of L to form M.

Q inhibits the reaction of O to form P.

S inhibits the reaction of O to form R.

Which reaction would prevail if both Q and S were present in the cell in high concentrations?

  1. \({\rm{L}}\, \to {\rm{M}}\)
  2. \({\rm{M}}\, \to {\rm{O}}\)
  3. \({\rm{L}}\, \to {\rm{N}}\)
  4. \({\rm{O}}\, \to {\rm{P}}\)
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